A strong acid ionizes completely in aqueous solution just like Hclo4
HClO4(l) + H2O(l) ------>H3O+(aq) + ClO4-(aq)
but a weak doesn't ionize completely in water
HClO2 + H2O ⇌ H3O+ + ClO2-
Flourine
Chlorine
Bromine
Iodine
Astatine
Saturated had as much solute that it can hold, supersaturated holds more than can normally be dissolved.
10 = 50
30 = 86
40 = 104
37 = 98.6
0 = 32
Solution of 0.25 M is prepared in two steps,
1) Calculate Amount of Solute:
Molar Mass of Solute: 342.3 g/mol
As we know,
Molarity = Moles / 1 dm³
or,
Moles = Molarity × 1 dm³
Putting Values,
Moles = 0.25 mol.dm⁻³ × 1 dm³
Moles = 0.25 moles
Now, find out mass of sucrose,
As,
Moles = Mass / M.mass
or,
Mass = Moles × M.mass
Putting Values,
Mass = 0.25 mol × 342.3 g.mol⁻¹
Mass = 85.57 g
2) Prepare Solution:
Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.
