The elements of heavy metals are used to absorb electrons in electron-dense stains.
<h3>
What are heavy metals?</h3>
A heavy metals are generally defined as metals with relatively high densities, atomic weight and atomic number.
They toxic and poisonous in nature. They occurs naturally and are very essential to life.
Arsenic, cadmium, lead, copper, nickel and mercury are the most commonly used heavy metals.
Electron staining means to absorb heavy metals of high scattering power to biological specimens which exhibit a small scattering power for electrons.
Thus, the elements of heavy metals are used to absorb electrons in electron-dense stains.
To learn more about heavy metals, refer to the link below:
brainly.com/question/3937595
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Volume:
2.00 x 11.0 x 11.0 => 242 cm³
mass : 213 g
D = m / V
D = 213 / 242
D = 0.880 g/cm³
Answer B
hope this helps!
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
Answer : The volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of
gas = (740-22.4) torr = 717.6 torr
= final pressure of
gas at STP= 760 torr
= initial volume of
gas = 280 mL
= final volume of
gas at STP = ?
= initial temperature of
gas = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K)
= final temperature of
gas = ![0^oC=273+0=273K](https://tex.z-dn.net/?f=0%5EoC%3D273%2B0%3D273K)
Now put all the given values in the above equation, we get:
![\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}](https://tex.z-dn.net/?f=%5Cfrac%7B717.6torr%5Ctimes%20280mL%7D%7B298K%7D%3D%5Cfrac%7B760torr%5Ctimes%20V_2%7D%7B273K%7D)
![V_2=242.2mL=0.2422L](https://tex.z-dn.net/?f=V_2%3D242.2mL%3D0.2422L)
Therefore, the volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Answer:
Balanced reaction:
3 H2 (g) + N2 (g) → 2 NH3 (g)
Use stoichiometry to convert g of H2 to g of NH3. The process would be:
g H2 → mol H2 → mol NH3 → g NH3
12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3
Explanation: See above
Hope this helps, friend.