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3 years ago

What happens when an acid dissolves

Chemistry

2 answers:

marysya [2.9K]3 years ago

8 0

Explanation:

When an acid is dissolved in water it forms hydrogen ions (H+) that combine with water to form the hydronium ion (H3O+) .

Margaret [11]3 years ago

3 0

Answer:

Acids are substances that when dissolved in water release hydrogen ions, H+(aq). ... When dissolved, bases release hydroxide ions, OH-(aq) into solution. Water is the product of an acid and base reacting. Chemists say that the acid and base cancel or neutralise each other, hence the reaction is known as "neutralisation".

Explanation:

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How many atoms of hydrogen-1 are in a 1.007-g sample?

Greeley [361]

I think it's 2 I tried looking it up because I was not sure.

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3 years ago

Which of the following atoms forms an ionic bond with a sulfur atom? (Points : 3)

elena-s [515]

Ionic bonds are formed when there is complete transfer of valence electrons between two atoms.

Electronegativity tells the trend of an atom to atract electrons.

You should search for the complete set of rules that indicate whether an ionic or covalent bond happens.

There are two relevant rules to state if whether an ionic bond will happen:

- When the difference of electronegativities between the two atoms is greater than 2.0, then the bond is ionic.

- When the difference is between 1.6 and 2.0, the bond is ionic if one of the elements is a metal.

You need to list the electronegativities of the five elements (there are tables with this information)

Element electronegativity

Cu: 1.9
H: 2.2
Cl 3.16
I: 2.66
S: 2.58

Differences:

Cu / S: 2.58 - 1.9 = 0.68
H / S: 2.58 - 2.2 = 0.38
Cl / S: 3.16 - 2.58 =0.58
I / S: 2.66 - 2.58 = 0.08

Those differences are too low to consider that the bond is ionic.

Then the answer is that none of those atoms forms an ionic bond with sulfur.

8 0

3 years ago

Read 2 more answers

What temperature does iron turn to a liquid?

swat32

Answer:2800 degrees

Explanation:when iron soild becomes a liquid at 2800 degrees Fahrenheit

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3 years ago

Which is the electron configuration for boron?

blagie [28]

Answer:

electron configuration for boron is 1s22s22p1

hope this helps :)

Explanation:

8 0

3 years ago

1.00 M CaCl2 Density = 1.07 g/mL

Lesechka [4]

Explanation:

Molarity of solution = 1.00 M = 1.00 mol/L

In 1 L of solution 1.00 moles of calcium chloride is present.

Mass of solute or calcium chloride = m

$m = 1 mol\times 111 g/mol = 111 g$

Mass of solution = M

Volume of solution = V = 1L = 1000 mL

Density of solution , d= 1.07 g/mL

$M=d\times V=1.07 g/mL\times 1000 mL=1,070 g$

1) The value of %(m/M):

$\frac{m}{M}\times 100=\frac{111 g}{1,070 g}\times 100=10.37\%$

2) The value of %(m/V):

$\frac{m}{V}\times 100=\frac{111 g}{1000 L}\times 100=11.1\%$

$Molality = \frac{\text{Moles of compound }}{\text{mass of solvent in kg}}$

$Normality=\frac{\text{Moles of compound }}{n\times \text{volume of solution in L}}$

n = Equivalent mass

n = $\frac{\text{molar mass of ion}}{\text{charge on an ion}}$

3) Normality of calcium ions:

Moles of calcium ion = 1 mol (1 $CaCl_2$ mole has 1 mole of calcium ion)

$n=\frac{40 g/mol}{2}=20$

$=\frac{1 mol}{20 g/mol\times 1L}=0.050 N$

4) Normality of chlorine ions:

Moles of chlorine ion = 2 mol (1 $CaCl_2$ mole has 2 mole of chlorine ion)

$n=\frac{35.5 g/mol}{1}=35.5$

$=\frac{2 mol}{35.5 g/mol\times 1L}=0.056 N$

Moles of calcium chloride = 1.00 mol

Mass of solvent = Mass of solution - mass of solute

= 1,070 g - 111 g = 959 g = 0.959 kg ( 1 g =0.001 kg)

5) Molality of the solution :

$\frac{1 mol}{0.959 kg}=1.043 mol/kg$

Moles of calcium chloride = $n_1=1mol$

Mass of solvent = 959 g

Moles of water = $n_2=\frac{959 g}{18 g/mol}=53.28 mol$

Mass of solvent = 959 g

6) Mole fraction of calcium chloride =

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{1mol}{1 mol+53.28 mol}=0.01842$

7) Mole fraction of water =

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{53.28 mol}{1mol+53.28 mol}=0.9816$

8) Mass of solution = m'

Volume of the solution= v = 100 mL

Density of solution = d = 1.07 g/mL

$m'=d\times v=1.07 g/ml\times 100 g= 107 g$

Mass of 100 mL of this solution 107 grams of solution.

9) Volume of solution = V = 100 mL

Mass of solution = M'' = 107 g

Mass of solute = m

The value of %(m/V) of solution = 11.1%

$11.1\%=\frac{m}{100 mL}\times 100$

m = 11.1 g

Mass of solvent = M''- m = 107 g -11.1 g = 95.9 g

95.9 grams of water was present in 100 mL of given solution.

3 0

3 years ago