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Leya [2.2K]
3 years ago
7

The strongest intermolecular interactions between hydrogen fluoride (HF) molecules arise from A) dipole dipole forces B) hydroge

n bonding C) ion dipole interactions D) ionic bondsE) London dispersion forces

Chemistry
2 answers:
Kipish [7]3 years ago
6 0

Answer:

B)

Explanation:

Hydrogen boding

Is a primarily electrostatic force of attraction between a hydrogen  atom which is covalently bound to a more electronegative atom or group, particularly the second-row elements.

zheka24 [161]3 years ago
3 0

Answer:

The answers are: A) dipole-dipole forces and B) hydrogen bonding

Explanation:

Hydrogen bonds are a class of bond that form from the attraction between a hydrogen atom and an atom that has a negative charge. This attraction is known by the name of dipole-dipole interaction.

In this case, since the hydrogen atom has a low electronegativity and since the fluorine atom has a high electronegativity, therefore, between them there will be a positive charge on the hydrogen atom and a negative charge on the fluorine atom. . In this way, they will have hydrogen bonds between the hydrogen atom and the fluorine atom.

The attached figure shows the bonds.

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The volume of a gas is 27.5 mL at 22.0°C and 0.974 atm. What will the volume be at 15.0°C and 0.993 atm? Use Ideal Gas Law (PV =
Scorpion4ik [409]

Answer:

26.3 mL

Explanation:

Step 1:

Obtaining an appropriate gas law from the ideal gas equation.

This is illustrated below:

From the ideal gas equation:

PV = nRT

Divide both side by T

PV/T = nR

At this stage, we'll assume the number of mole (n) to be constant.

Note: R is the gas constant.

PV/T = constant.

We can thus, write the above equation as:

P1V1/T1 = P2V2/T2

The above equation is called the general gas equation.

Step 2:

Data obtained from the question. This includes the following:

Initial volume (V1) = 27.5 mL

Initial temperature (T1) = 22.0°C = 22.0°C + 273 = 295K

Initial pressure (P1) = 0.974 atm.

Final temperature (T2) = 15.0°C = 15.0°C + 273 = 288K

Final pressure (P2) = 0.993 atm

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Step 3:

Determination of the final volume of the gas using the general gas equation obtained. This is illustrated below:

P1V1 /T1 = P2V2/T2

0.974 x 27.5/295 = 0.993 x V2/288

Cross multiply to express in linear.

295x0.993xV2 = 0.974x27.5x288

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V2 = (0.974x27.5x288)/(295x0.993)

V2 = 26.3 mL

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4 0
3 years ago
The pressure of a sample of gas is 500. mm Hg and the volume is 30.0 L. If the
Aloiza [94]

Answer: the new pressure will be 300mmHg

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6 0
3 years ago
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Answer:

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The molality of a solution that is made by dissolving a certain mass of benzene in 20.6g of carbon tetrachloride is 0.529m. How
antiseptic1488 [7]
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hope this helps!

6 0
3 years ago
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