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Leya [2.2K]
3 years ago
7

The strongest intermolecular interactions between hydrogen fluoride (HF) molecules arise from A) dipole dipole forces B) hydroge

n bonding C) ion dipole interactions D) ionic bondsE) London dispersion forces

Chemistry
2 answers:
Kipish [7]3 years ago
6 0

Answer:

B)

Explanation:

Hydrogen boding

Is a primarily electrostatic force of attraction between a hydrogen  atom which is covalently bound to a more electronegative atom or group, particularly the second-row elements.

zheka24 [161]3 years ago
3 0

Answer:

The answers are: A) dipole-dipole forces and B) hydrogen bonding

Explanation:

Hydrogen bonds are a class of bond that form from the attraction between a hydrogen atom and an atom that has a negative charge. This attraction is known by the name of dipole-dipole interaction.

In this case, since the hydrogen atom has a low electronegativity and since the fluorine atom has a high electronegativity, therefore, between them there will be a positive charge on the hydrogen atom and a negative charge on the fluorine atom. . In this way, they will have hydrogen bonds between the hydrogen atom and the fluorine atom.

The attached figure shows the bonds.

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The energies of the bonds broken in a certain reaction are greater than the energies of the bonds formed. Which one of the follo
frosja888 [35]

Answer:

a. The reaction is endothermic.

Explanation:

The heat involved in a chemical reaction is given by the enthalpy change (ΔH), which is equal to the balance between the chemical bonds that are broken (release energy) and the chemical bonds that are formed (need energy):

ΔH ≅ bonds broken - bonds formed

If broken bonds > bonds formed ⇒ ΔH > 0 ⇒ endothermic reaction

Therefore, the reaction is endothermic (it requires energy).

4 0
2 years ago
Difine the term compound​
AlexFokin [52]

Answer:

Its when like two pure substances are like combined into one.

Explanation:

8 0
2 years ago
A reaction is exothermic when Group of answer choices weak bonds break and strong bonds form. strong bonds break and weak bonds
Leona [35]

Answer:

weak bonds break and strong bonds form

Explanation:

An exothermic reaction is a chemical reaction in which heat energy is evolved during the reaction process.

Bond formation requires energy while bond breakage releases energy. More energy is needed for the formation of weak bonds as compared to strong bonds.

<em>Hence, when weak bonds break, they release more energy than needed to make a corresponding strong bond leading to the release of the remaining energy as heat.</em>

6 0
3 years ago
Calculate the solubility of o2 in water at a partial pressure of o2 of 120 torr at 25 ̊c. the henry's law constant for o2 at 25
Vladimir79 [104]

Answer:

1) 2.054 x 10⁻⁴ mol/L.

2) Decreasing the temperature will increase the solubilty of O₂ gas in water.

Explanation:

1) The solubility of O₂ gas in water:

  • We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,
  • where, Cgas is the solubility if gas,
  • K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),
  • P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).
  • Cgas = K P = (1.3 x 10⁻³ mol/l atm) (0.158 atm) = 2.054 x 10⁻⁴ mol/L.

2) The effect of decreasing temperature on the solubility O₂ gas in water:

  • Decreasing the temperature will increase the solubilty of O₂ gas in water.
  • When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.
  • Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.


6 0
2 years ago
Read 2 more answers
A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec
koban [17]

Answer:

Ca^{2+}  and  Co^{2+}

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, Ca_2 and Co_2

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding Li_2SO_4 to it precipitation takes place.

Precipitate is as follows,

Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)

Thus,

Ca^2^+ is present

When Li_3PO_4 is added again precipitation takes place.

Therefore the reaction is as follows,

Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)

Therefore,

Ca^{2+}  and  Co^{2+} are present in the solution

3 0
3 years ago
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