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posledela
3 years ago
13

Match the following numbers with the correct number of significant digits they possess. Answers may repeat. (4 points)

Chemistry
1 answer:
mezya [45]3 years ago
8 0

(B. 3) 172 All nonzero digits are significant.

(A. 4) 450.0 x 10^3 Trailing zeroes after the decimal point are significant.

(A. 4) 3427 All nonzero digits are significant.

(B. 3) 0.0000455 Leading zeroes are not significant.

(B. 3) 0.00456 Leading zeroes are not significant.

(C. 5) 2205.2 Zeroes between nonzero digits are significant.

(C. 5) 107.20 Trailing zeroes after the decimal point are significant.

(B. 3) 0.0473 Leading zeroes are not significant.

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Oil or Lipid + Base lead to Glycerol and Soap

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What happens to the energy of an electron if it moves from one energy level to another
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The energy levels in an atom are similar to the rungs of a ladder, but they get closer together as they get farther from the nucleus. For an electron to move from one energy level to the next higher level, it must gain the right amount of energy. If less than that amount is available, the electron stays where it is.

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Draw the alkyne formed when 1,1-dichloro-4-methylpentane is treated with an excess of a strong base such as sodium amide. (give
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How many moles are in 300 kilograms of carbon monoxide
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6 0
2 years ago
Do anyone know how to do question B
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Answer:

a) IUPAC Names:

                   1) (<em>trans</em>)-but-2-ene

                   2) (<em>cis</em>)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

7 0
2 years ago
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