C is the answer because he wants to know if less force is needed to pull on a slippery surface which reduces friction
<h3>i think its help</h3><h3>iron ( III )</h3><h3>oxide ( Fe,O )</h3>
n = PV/RT
p = 1.6 atm
v = 12.7L
R = 0.0821
T = 24°C which is equivalent to 297.15 degrees k
n = (16 × 12.7) / (0.0821 × 297.15)
n = 20.32 / 24.39
n = 0.83 mol
C = 12.90
H = 1.0079
C2 = 12.010 × 2 = 24.02
H6 = 1.0079 × 6 = 6.0474
C2H6 = 30.0674
Ethane times n which is 30.0674 × 0.83mol
= 24.95 grams of C2H6. Which is Ethane.
The speed of sound is given by the formula
Speed of sound = square root (Young's Modulus/density)
Young's modulus for gold = 78 GPa which is 7.8 * 10^10 Pa
Speed of sound = (7.8 * 10^10 / 19.3 ) = sqrt (4.04 * 10^9 )
Speed of sound = 6.36 * 10^4 m/s <<<=== answer.
Answer:
92.37°C
Explanation:
Assuming the volume remains the same in both the states ( bicycle tire).
Then as per ideal gas equation
where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states
Given:
P1 = 1.34 atm, T1 = 33.0 ° C = 306K
P2 = 1.60 atm, T2 = ?
1.34/306 = 1.60/T_2
⇒ T2 = 1.60×306/1.34
= T2= 365.37K= 92.37°C
