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Len [333]
3 years ago
8

Ap biology lab -what barriers might hinder the acquisition of plasmids

Chemistry
2 answers:
kaheart [24]3 years ago
8 0
Restriction as a barrier to transformation apparently contributes to sexual isolation since horizontal transfer can encompass chromosomal DNA and plasmids. I hope my answer has come to your help. God bless and have a nice day ahead!
Lina20 [59]3 years ago
6 0

Answer:

The barriers could be:

-Control of plasmid replication by antisense RNA.

-Control of plasmid replication by proteins and repeated sequences.

-Incompatibility mediated by partition systems.

Explanation:

Plasmids are genetic elements that can often be a strain on the bacteria. To prevent the elimination of the plasmid, they have a control system that has to do with the number of copies. These systems respond and control to the changes that can occur in an increase in the number of copies as well as in their decrease. The systems described above are primarily responsible for plasmid incompatibility.

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Benzene is a minor component of gasoline. The standard molar enthalpy of formation of benzene C7H16(l) is 48.95 kJ/mol. For the
Radda [10]

Answer:

-3135.47 kJ/mol

Explanation:

Step 1: Write the balanced equation

C₆H₆(l) + 7.5 O₂(g) ⇒ 6 CO₂(g) + 3 H₂O(g)

Step 2: Calculate the standard enthalpy change of the reaction (ΔH°r)

We will use the following expression.

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

where,

n: moles

ΔH°f: standard enthalpies of formation

p: products

r: reactants

ΔH°r = 6 mol × ΔH°f(CO₂(g)) + 3 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C₆H₆(l)) - 7.5 mol × ΔH°f(O₂(g))

ΔH°r = 6 mol × (-393.51 kJ/mol) + 3 mol × (-241.82 kJ/mol) - 1 mol × (48.95 kJ/mol) - 7.5 mol × 0 kJ/mol

ΔH°r = -3135.47 kJ

Since this enthalpy change is for 1 mole of C₆H₆(l), we can express it as -3135.47 kJ/mol.

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Evan has a rock. The rock has a mass of 12g and a volume of 4cm3. What is the density of the rock?
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Hope that helps!!!
5 0
3 years ago
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