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raketka [301]
3 years ago
7

What state of matter change is rain?

Chemistry
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

The state of matter of rain is liquid. Clouds are 2 states of matter, liquid and gas

Explanation:

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The flame in a torch used to cut metal is produced by burning acetylene (C2H2) in pure oxygen. Assuming the combustion of 1 mole
Nookie1986 [14]

Answer:

19.8 kg of C₂H₂ is needed

Explanation:

We solve this by a rule of three:

If 1251 kJ of heat are relased in the combustion of 1 mol of acetylene

95.5×10⁴ kJ of heat may be released by the combustion of

(95.5×10⁴ kJ . 1) /1251kJ = 763.4 moles of C₂H₂

Let's convert the moles to mass → 763.4 mol . 26 g/1 mol = 19848 g

If we convert the mass from g to kg →  19848 g . 1kg / 1000g = 19.8 kg

7 0
3 years ago
Read 2 more answers
A neutral atom of Cl-37 has
Ostrovityanka [42]

Answer:

17 protons, 20 neutrons, and 17 electrons​.

Explanation:

A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.

Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

The mass number of this neutral atom of Cl-37 is 37 and we know that the atomic number (number of protons) of chlorine is 17. Also, the atomic number of an element is equal to the number of its electrons.

A neutral atom of Cl-37 has 17 protons, 20 neutrons, and 17 electrons.

Hence, a neutral atom of Cl-37 can be identified based on its number of protons because it represent its atomic number, which is what is used to differentiate an atom of an element from the atom of another chemical element.

6 0
3 years ago
A compound is 57.1% oxygen and the remainder carbon. using oxygen as the standard (16 amu) and assuming a 1:1 atom ratio, calcul
Delicious77 [7]
Let's start with the amount given in percent. Let our basis be 100 grams of compound. So, that means that in this amount, 57.1 g is oxygen and 100-57.1=42.9 g is carbon. Since there is 1:1 atom ratio, it also means that moles oxygen = moles carbon.

Moles = Mass/Relative Mass
Let x be the relative mass of oxygen

57.1/16 = 42.9/x
Solving for x,
<em>x = 12.02 amu</em>
4 0
3 years ago
How many mL of a 4% mass/volume Mg(NO3)2 solution would contain 1.2 grams of magnesium nitrate?
Phoenix [80]
4% mass / volume :

4 g ---------> 100 mL
1.2 g ------- ? mL

V = 1.2 * 100 / 4

V = 120 / 4

V = 30 mL

hope this helps!

7 0
3 years ago
if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa
bija089 [108]

Answer:

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂     Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂  

p₁ = 485 kPa; V₁ =              648 mL  

p₂ = ?;            V₂ = 0.15 L = 150 mL      Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa

4 0
3 years ago
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