If 82.3 l of an ideal gas is cooled from 46 degrees calius to -166 what will the volume of the gas become

1 answer:

5 0

Temperature is directly related to volume. Note that temperature used is Kelvin, so you need to convert both of them into Kelvin

With that information, you can derive this equation:
T1/T2=V1/V2
<span>V2= V1*T2/ T1

V2=</span>82.3 * (-166+273.15) / (46+273.15)<span>
V2= 82.3 * </span>107.15 / 319.15
V2= 27.63L

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How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

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<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$