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3 years ago

If 82.3 l of an ideal gas is cooled from 46 degrees calius to -166 what will the volume of the gas become

1 answer:

5 0

Temperature is directly related to volume. Note that temperature used is Kelvin, so you need to convert both of them into Kelvin

With that information, you can derive this equation:
T1/T2=V1/V2
<span>V2= V1*T2/ T1

V2=</span>82.3 * (-166+273.15) / (46+273.15)<span>
V2= 82.3 * </span>107.15 / 319.15
V2= 27.63L

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3. Which of the following sentences apply to neutrons? a. have a negative charge. b. circle around the atom nucleus. c. are the

DerKrebs [107]

Answer:

d.have a mass of 1 amu..

Explanation:

Does not match a as the answer for a is electrons B.electron circle around the nucleus because neutrons are inside the nucleus.C.proton and neutrons make the nucleus so the only answer left is .d .which is correct

3 0

2 years ago

Predict the missing product of this equation<br><br><br>1 MgF2 + 1 Li2CO3 -> 1 ______ +2LiF

ch4aika [34]

Answer:

MgCO₃

Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

MgF₂ (aq) —> Mg²⁺ + 2F¯

Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯

MgF₂ + Li₂CO₃ —>

Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Therefore, the missing part of the equation is MgCO₃

8 0

3 years ago

How many moles of hci are needed to form 230 moles of ci2?

LekaFEV [45]

<span>The answer is 335 dm³.</span>

4 0

3 years ago

How many molecules are produced when 59.4 g of water is decomposed by electrolysis to make oxygen and hydrogen?

BabaBlast [244]

The answer will be

.
.
.
4.88 x 1023 molecules of O2

8 0

3 years ago

What are the spectator ions in the reaction between mg(oh)2 (aq) and hcl (aq)?

vivado [14]

The spectator ions in the reaction between aqueous $Mg(OH)_2$ and aqueous HCl would be $Mg^{2+$ and $Cl^-$ ions.

<h3>What are spectator ions?</h3>

Spectator ions are anions or cations that exist both as reactants and as products in a reaction. Their forms remain unchanged both in the reactants and in the products.

Aqueous $Mg(OH)_2$ and aqueous HCl react according to the following equation:

$Mg (OH)_2 (aq) + 2HCl (aq) --- > MgCl_2 (aq) +2 H_2O (l)$

Before the reaction, $Mg^{2+$ and $Cl^-$ existed in the reactants as $Mg(OH)_2$ and HCl respectively. After the reaction, $Mg^{2+$ and $Cl^-$ exist as $MgCl_2$ in the product.

Thus, the spectator ions in this case are $Mg^{2+$ and $Cl^-$ ions because their forms did not change after the reaction.

More on spectator ions can be found here: brainly.com/question/28913274

#SPJ1

6 0

1 year ago