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Kipish [7]
3 years ago
10

What is the name for the compound BrCl?

Chemistry
1 answer:
UNO [17]3 years ago
8 0

Compound name:

Bromine chloride

Bond type:

Covalent Bond

Reasoning for Bond type:

Formed between nonmetal and nonmetal atoms

Br (Bromine) is a nonmetal. Also, known as a liquid.

Cl (Chlorine) is a nonmetal. Also, know as a gas.

Use this website for more element information:

https://ptable.com/#Properties

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If electricity cannot be destroyed or created then why do we got to pay for electricity?
icang [17]

Energy cannot be destroyed or created. Electricity is a form of energy which has to be created from other forms of energy. We have to pay for the creation of electricity because it requires certain resources to transform other energies into electricity.

5 0
3 years ago
When a gas in a cylinder is compressed at constant temperature by a piston, the pressure of the gas increases. Consider the foll
Marizza181 [45]

Answer:

Answer below!!

Explanation:

The volume of a gas is inversely proportional to presure keeping the temperature the same.

Hope I helped!!!

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4 0
3 years ago
Which of the following occurs because of unequal heating of the Earth's surface?
gladu [14]
The answer is Winds ..................
5 0
3 years ago
Read 2 more answers
Metals are ductile. This allows them to _____.
Gwar [14]
I think the answer is B. But I am not sure 
6 0
4 years ago
Read 2 more answers
If an unknown sample contains 39.04% sulfuric acid by mass, then a 0.9368 g of that sample would require _____ mL of 0.2389 M Na
bonufazy [111]

Answer:

A) 31.22

Explanation:

The reaction of sulfuric acid with NaOH is:

H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O

To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.

<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>

0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =

3.7289x10⁻³moles H₂SO₄

And moles of NaOH that you require to neutralize the acid are:

3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =

7.4578x10⁻³ moles NaOH

Using a 0.2389M NaOH solution:

7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL

Right answer is:

<h3>A) 31.22 </h3>

5 0
3 years ago
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