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vova2212 [387]
3 years ago
8

To lift an objet weighing 21,000N, how much force is needed on a piston with an area of 0.060 meters squared if the platform bei

ng lifted has an area of 3.0 meters squared?
Physics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

The weight required on the piston equals 420 Newtons.

Explanation:

from the principle of transmission of pressure in a hydraulic lift  we have

\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}

where

'F' is the force that acts on the piston

'A' is the area of the piston.

Since the force in the question is 21000 Newtons thus upon putting the values in the above equation we get

\frac{21000}{3.0m^{2}}=\frac{W}{0.06m^{2}}

Solving for W we get

W=\frac{21000}{3}\times 0.06\\\\\therefore W=420Newtons

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The formula for half-life is:

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3 years ago
Please help on this one
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Un cuerpo se lanza verticalmente hacia arriba con una velocidad de 13 m/s. ¿Cuánto tiempo tarda en alcanzar la altura máxima? a)
Elena L [17]

Answer:

D. 1.33 segundos.

Explanation:

El cuerpo es experimenta un movimiento en caída libre al modificarse su velocidad por efecto de la gravitación terrestre. Este cuerpo alcanza instantáneamente el reposo cuando se encuentra a su altura máxima, el tiempo puede obtenerse sabiendo la aceleración y las velocidades incial y final a partir de la siguiente ecuación cinemática:

v = v_{o}+g\cdot t

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v_{o} - Velocidad inicial del cuerpo, medida en metros por segundo.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

t - Tiempo, medido en segundos.

Ahora se despeja el tiempo:

t = \frac{v-v_{o}}{g}

Si v_{o} = 13\,\frac{m}{s}, v=0\,\frac{m}{s} y g = -9.807\,\frac{m}{s^{2}}, entonces:

t = \frac{0\,\frac{m}{s}-13\,\frac{m}{s}}{-9.807\,\frac{m}{s^{2}} }

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Answer:

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300 cm/min² × (1 m / 100 cm) × (1 min / 60 s)² = 8.33×10⁻⁴ m/s²

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