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pantera1 [17]
4 years ago
13

Fill in the blanks

Physics
1 answer:
just olya [345]4 years ago
4 0

Answer:

An atom that loses a electron is called a cation and has an overall positive charge.

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Since this object is traveling at terminal velocity, what must be the value of Fd? (HINT: how to the lengths of both arrows comp
Juli2301 [7.4K]

The magnitude of the air drag when the object is traveling at terminal velocity is C. 850 Newtons

Explanation:

There are only two forces acting on the object here:

- The force of gravity, of magnitude F_g = 850 N, acting downward

- The air drag, F_d, acting upward

Therefore, the equation of motion for the object is

F_g - F_d = ma

where m is the mass of the object and a its acceleration.

The object in this problem is traveling at terminal velocity: this means that the acceleration is zero, so

a = 0

Therefore the equation becomes

F_d = F_g

which means that the magnitude of the air resistance is equal to the magnitude of the force of gravity:

F_d = 850 N

Learn more about acceleration and Newton laws of motion here:

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#LearnwithBrainly

8 0
4 years ago
Derive mean in science <br>​
eduard

Explanation:

derive its name from a Native American word meaning wild onion

6 0
3 years ago
Carbon and hydrogen are examples of pure substances or
Ede4ka [16]
The are elements on the periodic table
7 0
4 years ago
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Calculate the density of a solid of mass 20kg if it occupies a volume of 4m³​
choli [55]

Answer:

Density=Mass/Volume

            =20/4 kg/m^3

            =5 kg/m^3

4 0
3 years ago
Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up
nignag [31]

Answer:

The acceleration of the train is 5 m/s².

Explanation:

Acceleration is the change in velocity over a given time interval.

Therefore, acceleration is given as:

a=\frac{v_{f}-v_{i}}{\Delta t}

Where, v_{i}\textrm{ and }v_{f} are initial and final velocities and \Delta t is the time interval.

Here, v_{i}=5\textrm{ m/s},v_{f}=45\textrm{ m/s},\Delta t=8\textrm{ s}

This gives,

a=\frac{45-5}{8}=\frac{40}{8}=5\textrm{ }m/s^{2}

Therefore, the acceleration of the train is 5 m/s².

4 0
3 years ago
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