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larisa86 [58]
3 years ago
14

Nonuniform positive acceleration

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

It means that acceleration changes with time.
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The volume of a container is reported as 3.49 ft3. what is the volume in units of in3?
Kobotan [32]

The volume in units of 6.03x10^3 in3

1ft = 12 inch

So to convert foot into inches we have to multiply by 12

The volume of container = 3.49ft^3

=3.49×12×12×12

= 6030.72 in^3

<h3>What is the volume of a container?</h3>

The amount of space a container encloses, or how much room is inside of it, is measured by its volume. The volume of a box can be calculated using this straightforward formula: volume V = L × W × H for a box with height H, width W, and length L.

Many different units can be used, however because of the way this formula is written, the volume would have length to the third power dimensions. For instance, if the container's measurements are given in metres, the capacity of the box will be given in metres squared, or m3.

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2 years ago
What element shares the property of forming ions with a 1+ charge?
Oduvanchick [21]

Answer:

the Group 1A metals such as sodium and potassium form +1 charges,

Explanation:

5 0
3 years ago
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What are five examples that illustrate a machine or a person doing work on another?
valentina_108 [34]
I sort of understand but what does it mean by.... Another?
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3 years ago
Let x define the position of an object such that x =
timama [110]
See the attached picture for answers

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3 years ago
A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t
Mumz [18]

Answer:

v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

6 0
3 years ago
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