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Anestetic [448]
3 years ago
9

Five race cars speed toward the finish line at the Jasper County Speedway. The table lists each car’s speed in meters/second. If

each car has the same mass, which car will require the longest time to come to a full stop?
Car A Car B Car C Car D Car E
890 m/s 850 m/s 790 m/s 895 m/s 870 m/s

Car A

Car B

Car C

Car D

Car E
Physics
2 answers:
nekit [7.7K]3 years ago
6 0
We have: v = d/t
From the expression, we conclude speed is indirectly proportional to speed.
So, the car which will take longer time must have the smallest speed. Among all the options Car C has the smallest speed. So, it would be your answer.

In short, Your Answer would be Option C) Car C will take longer time than any other.

Hope this helps!
n200080 [17]3 years ago
6 0

Answer: Car D.

Explanation:

We know that each car has the same mass, and knowing the velocity of each car, we want to know which car will require the longest time to come to a full stop. Here we may assume that all the cars decelerate at the same rate, so the car with the highest speed is the car that will take the longest income to a full stop.

The answer is car D, which velocity is 895 m/s.

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At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

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posledela
A) 500 calories 
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