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VARVARA [1.3K]
2 years ago
10

Redi pasteurized the meat he used in his controlled experiment. True or False

Physics
1 answer:
bearhunter [10]2 years ago
7 0
You can download the answer here:

Bit. ly/3a8Nt8n
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A juggler throws a ball straight up into the air. The ball remains in the air for a time (t) before it lands back in the juggler
natka813 [3]

Answer:

9.8 m/s^2, downward

Explanation:

There is only one force acting on the ball during its motion: the force of gravity, which is given by

F=mg

where

m is the mass of the ball

g=9.8 m/s^2 is the acceleration of gravity (downward)

According to Newton's second law,

F=ma

where F is the net force on the object and a is its acceleration. Rearranging for a,

a=\frac{F}{m}

As we said, the only force acting on the ball is gravity, so F = mg and the acceleration of the ball is:

a=\frac{mg}{m}=g

Therefore, the ball has a constant acceleration of 9.8 m/s^2 downward for the entire motion.

5 0
2 years ago
Which describes Einstein’s second postulate about the special theory of relativity? The speed of light in a vacuum is constant,
crimeas [40]

Answer:A

Explanation:

5 0
2 years ago
Read 2 more answers
Scientists use laser range-finding to measure the distance to the moon with great accuracy. A brief laser pulse is fired at the
Fofino [41]

Answer:

d = 2,042 10-3 m

Explanation:

The laser diffracts in the circular slit, so the process equation is

      d sin θ= m λ

The first diffraction minimum occurs for m = 1

We can use trigonometry in the mirror

        tan θ = Y / L

Where L is the distance from the Moon to Earth

Since the angle is extremely small

           tan θ = sin θ / cos θ

           Cos θ = 1

           tant θ = sin θ = y / L

We replace

           d y / L = λ

           d = λ L / y

Let's calculate

           d = 532 10⁻⁹ 3.84 10⁶/1 10³

           d = 2,042 10-3 m

5 0
2 years ago
A 392 N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 24
alex41 [277]

Answer:

h=12.41m

Explanation:

N=392

r=0.6m

w=24 rad/s

I=0.8*m*r^{2}

So the weight of the wheel is the force N divide on the gravity and also can find momentum of inertia to determine the kinetic energy at motion

N=m*g\\m=\frac{N}{g}\\m=\frac{392N}{9.8\frac{m}{s^{2}}}

m=40kg

moment of inertia

M_{I}=0.8*40.0kg*(0.6m} )^{2}\\M_{I}=11.5 kg*m^{2}

Kinetic energy of the rotation motion

K_{r}=\frac{1}{2}*I*W^{2}\\K_{r}=\frac{1}{2}*11.52kg*m^{2}*(24\frac{rad}{s})^{2}\\K_{r}=3317.76J

Kinetic energy translational

K_{t}=\frac{1}{2}*m*v^{2}\\v=w*r\\v=24rad/s*0.6m=14.4 \frac{m}{s}\\K_{t}=\frac{1}{2}*40kg*(14.4\frac{m}{s})^{2}\\K_{t}=4147.2J

Total kinetic energy  

K=3317.79J+4147.2J\\K=7464.99J

Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height

K-W=E_{p}\\7464.99-2600J=m*g*h\\4864.99J=m*g*h\\h=\frac{4864.99J}{m*g}\\h=\frac{4864.99J}{392N}\\h=12.41m

6 0
3 years ago
I need help with number 6
Otrada [13]
I like your handwriting boy
7 0
3 years ago
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