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WINSTONCH [101]
3 years ago
6

A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th

e effects of air drag and rolling friction. Find the following. (a) the normal force exerted by the pavement on the tires.

Physics
1 answer:
lianna [129]3 years ago
6 0

Answer:

F_n = 7509.33\ N

Explanation:

given,

radius of curve = 166 m

angle of the banked road = 11°

mass of car = 736 Kg

speed of the curve = 81 km/h

                                = 81 x 0.278 = 22.52 m/s

normal force acting on the tires

on tire there will be two force acting on it

first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.

F_n = m g cos \theta+ \dfrac{mv^2}{r} sin \theta

F_n = 736 \times 9.8 \times cos 11^0+\dfrac{736 \times 22.52^2}{166} sin 11^0

F_n = 7080.28+429.047

F_n = 7509.33\ N

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Answer:

Choice A.

Nearness to a body of water causes an increase in humidity, due to the higher rate of evaporation.

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That which flows on uniformly, of which a day is a logical portion, is called time. True or False
mr_godi [17]
The answer to the statement is true because the day is of the logical proportion it has to be time.
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3 years ago
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A schoolbus accelerates to 65 mph and enters the freeway. It travels for 2.3 hours at that speed while on the freeway. What's th
PtichkaEL [24]

Answer:

The distance travelled on the freeway is 149.5 miles.

Explanation:

The school bus travels on the freeway at constant speed. According to the statement, we need to calculate the distance travelled by the vehicle by means of the following formula:

x = v\cdot t (1)

Where:

x - Traveled distance, in miles.

v - Speed, in miles per hour.

t - Time, in hours.

If we know that v = 65\,\frac{mi}{h} and t = 2.3\,h, then the distance travelled by the school bus is:

x = v\cdot t

x =  \left(65\,\frac{mi}{h} \right)\cdot (2.3\,h)

x = 149.5\,mi

The distance travelled on the freeway is 149.5 miles.

5 0
2 years ago
A reservoir located in the mountain 250 m above sea level flows through a pipe to a hydroelectric plant in a town at sea level.
Pavlova-9 [17]

Answer:

     v₂ = 70 m / s

Explanation:

For this exercise let's use Bernoulli's equation

where subscript 1 is for the top of the mountain and subscript 2 is for Tuesday's level

 

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂

indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute

         ρ g y₁ = ½ ρ v₂²

         v₂ = \sqrt {2g \ y_1}

let's calculate

         v₂ = √( 2 9.8 250)

         v₂ = 70 m / s

6 0
3 years ago
At a department store, you adjust the mirrors in the dressing room so that they are parallel and 6.2 ft apart. You stand 1.8 ft
barxatty [35]

Answer:

<em>a) 3.6 ft</em>

<em>b) 12.4 ft</em>

Explanation:

Distance between mirrors = 6.2 ft

difference from from the mirror you face = 1.8 ft

a) you stand 1.8 ft in front of the mirror you face.

According to plane mirror rules, the image formed is the same distance inside the mirror surface as the distance of the object (you) from the mirror surface. From this,

your distance from your first "front" image = 1.8 ft + 1.8 ft = <em>3.6 ft</em>

b) The mirror behind you is 6.2 - 1.8 = 4.4 ft behind you.

the back mirror will be reflected 3.6 + 4.4 = 8 ft into the front mirror,

the first image of your back will be 4.4 ft into the back mirror,

therefore your distance from your first "back" image = 8 + 4.4 = <em>12.4 ft</em>

8 0
3 years ago
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