A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th
e effects of air drag and rolling friction. Find the following. (a) the normal force exerted by the pavement on the tires.
1 answer:
Answer:
Explanation:
given,
radius of curve = 166 m
angle of the banked road = 11°
mass of car = 736 Kg
speed of the curve = 81 km/h
= 81 x 0.278 = 22.52 m/s
normal force acting on the tires
on tire there will be two force acting on it
first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.
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Answer:
(a) if she increases the tension in the string is increased by 15%, the fundamental frequency will be increased to 740.6 Hz
(b) If she decrease the length of the the string by one-third the fundamental frequency will be increased to 840 Hz
Explanation:
(a) The fundamental, f₁, frequency is given as follows;
Where;
T = The tension in the string
μ = The linear density of the string
L = The length of the string
f₁ = The fundamental frequency = 560 Hz
If the tension in the string is increased by 15%, we will have;
Therefore, if the tension in the string is increased by 15%, the fundamental frequency will be increased by a fraction of 0.3225 or 32.25% to 740.6 Hz
(b) When the string length is decreased by one-third, we have;
The new length of the string, = 2/3·L
The value of the fundamental frequency will then be given as follows;
When the string length is reduced by one-third, the fundamental frequency increases to one-half or 50% to 840 Hz.