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WINSTONCH [101]

3 years ago

6

A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th

e effects of air drag and rolling friction. Find the following. (a) the normal force exerted by the pavement on the tires.

1 answer:

lianna [129]3 years ago

6 0

Answer:

$F_n = 7509.33\ N$

Explanation:

given,

radius of curve = 166 m

angle of the banked road = 11°

mass of car = 736 Kg

speed of the curve = 81 km/h

= 81 x 0.278 = 22.52 m/s

normal force acting on the tires

on tire there will be two force acting on it

first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.

$F_n = m g cos \theta+ \dfrac{mv^2}{r} sin \theta$

$F_n = 736 \times 9.8 \times cos 11^0+\dfrac{736 \times 22.52^2}{166} sin 11^0$

$F_n = 7080.28+429.047$

$F_n = 7509.33\ N$

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The initial speed of a body is 7.1 m/s. What is its speed after 2.23 s if it accelerates uniformly at 2.64 m/s 2 ? Answer in uni

Nana76 [90]

13.0m/s

1.2m/s

Explanation:

Given parameters:

Initial speed of the body = 7.1m/s

time taken = 2.23s

Acceleration = 2.64m/s²

Unknown:

Final speed = ?

Solution:

Acceleration is the rate of change of velocity with time.

a = $\frac{V - U}{T}$

a = acceleration

V = final speed

U = initial speed

T = time taken

Input the variables and solve for V;

2.64 = $\frac{V - 7.1}{2.23}$

V - 7.1 = 5.9 expression 1

V = 5.9 + 7.1 = 13.0m/s

B

Using the same parameters, the speed after a uniform deceleration of -2.64m/s², the negative sign implies deceleration;

from expression 1;

V - 7.1 = -5.9

V = -5.9 + 7.1 = 1.2m/s

learn more:

Acceleration brainly.com/question/3820012

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3 years ago

A projectile has an initial horizontal velocity of 15 meters per second and an initial vertical velocity of 25 meters per second

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Answer:

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3 years ago

A rectangular loop of wire with width w = 5 cm, length L = 10cm, mass m = 40 g, and resistance R = 20 mΩ has an initial velocity

zhuklara [117]

Answer:

The loop penetrate 4 cm into the magnetic field.

Explanation:

Given that,

Width w= 5 cm

Length L= 10 cm

mass m = 40 g

Resistance R = 20 mΩ

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We need to calculate the induced emf

Using formula of emf

$\epsilon=v_{0}Bw$

Put the value into the formula

$\epsilon =1\times2\times5\times10^{-2}$

$\epsilon =10\times10^{-2}\ volt$

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Using Lenz's formula

$i=\dfrac{\epsilon}{R}$

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Using formula of acceleration

$a=\dfrac{F}{m}$

Put the value in to the formula

$a=\dfrac{0.5}{40\times10^{-3}}$

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Hence, The loop penetrate 4 cm into the magnetic field.

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3 years ago