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Sonbull [250]
3 years ago
6

How does the change in the sa/v ratio compare with the change in distance from the center of the cell to the nearest face?

Physics
1 answer:
Ivanshal [37]3 years ago
3 0
<span>Answer: I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4(pi)r^2, while V = (3/4)(pi)r^3. The ratio = (4(pi)r^2)/((3/4)(pi)r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.</span>
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Explanation:

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If two balls have the same volume,
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Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

  • 1. Ball A will have the greater density
  • 2. Ball C and Ball D have the same density.
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The density of an object is given as its mass per unit volume of the object.

Mathematically;.

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For Case 1:

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For Case 2:

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  • Vd = (1/3)Vc

  • Md = (1/3)Mc

  • D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd

  • D(c) = D(d).

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For Case 3:

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For case 4:

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Therefore, Ball X and Ball Y have the same density.

Read more:

brainly.com/question/18110802

8 0
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6 0
3 years ago
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sveta [45]

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Explanation:

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Therefore the current in the circuit is 80 amperes :)

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