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Sonbull [250]
3 years ago
6

How does the change in the sa/v ratio compare with the change in distance from the center of the cell to the nearest face?

Physics
1 answer:
Ivanshal [37]3 years ago
3 0
<span>Answer: I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4(pi)r^2, while V = (3/4)(pi)r^3. The ratio = (4(pi)r^2)/((3/4)(pi)r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.</span>
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A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius cylinder at the to
Elodia [21]

As we know the relation between linear speed and angular speed as

v = R\omega

we will say

v = 8 m/s

R = 0.05 m

so here we can say that angular speed will be given as

\omega = \frac{8}{0.05}

\omega = 160 rad/s

so it is rotating at angular speed 160 rad/s

7 0
3 years ago
Trace fossils are much more common than body fossils. Which of the following best explains why trace fossils are more common?
Anika [276]
<span>the remains or impression of a prehistoric organism preserved in petrified form or as a mold or cast in rock.</span>
7 0
3 years ago
A pressure cylinder has a diameter of 150-mm and has a 6-mm wall thickness. What pressure can this vessel carry if the maximum s
myrzilka [38]

Answer:

p = 8N/mm2

Explanation:

given data ;

diameter of cylinder =  150 mm

thickness of cylinder = 6 mm

maximum shear stress =  25 MPa

we know that

hoop stress is given as =\frac{pd}{2t}

axial stress is given as =\frac{pd}{4t}

maximum shear stress = (hoop stress - axial stress)/2

putting both stress value to get required pressure

25 = \frac{ \frac{pd}{2t} -\frac{pd}{4t}}{2}

25 = \frac{pd}{8t}

t = 6 mm

d = 150 mm

therefore we have pressure

p = 8N/mm2

7 0
3 years ago
when charge 2 is 3.0 m away from charge 1, the strength of the electric force on charge 2 by charge 1 is 0.80 n. if instead, cha
Nikolay [14]

The strength of the electrostatic force is inversely proportional to the square of the distance

between the charges. If the distance is doubled, the force is 1/4.

The new force is 0.80/4 = 0.20 N.

<h3>What is electrostatic force? </h3>

Electrostatic force is the attractive or repulsive force that exists between two charged particles. Also known as Coulomb interaction or Coulomb force. For example, the electrostatic forces between the protons and electrons of an atom are responsible for the stability of the atom.

The force acting along a line joining two point charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

F=K |\frac{q_{1} q_{2}}{r^{2} }   |

In the above formula, k is arbitrary and can be chosen to be any positive value. Since k is a constant, I chose to give the value of k as follows:

Therefore, with q₁ and q₂ values ​​of 1 and r = 1 (two charges with 1 Coulomb charge each at a distance of 1 m), we get F = 9 \times 10^9 N. In the above equation, ε₀ is given as the permittivity of free space and its value in SI units is 8.854\times10^{-12} C^{2} N^{-1}  m^{-2}.

To learn more about electrostatic force , visit:

brainly.com/question/14870624

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5 0
1 year ago
A car travels at a constant speed around a circular track whose radiu is 2.6 km. The goes once arond the track in 360s . What is
AveGali [126]

Answer:

Centripetal acceleration = 0.79 m/s²

Explanation:

<u>Given the following data;</u>

Radius, r = 2.6 km

Time = 360 seconds

<em><u>Conversion:</u></em>

2.6 km to meters = 2.6 * 1000 = 2600 meters

To find the magnitude of centripetal acceleration;

First of all, we would determine the circular speed of the car using the formula;

Circular \; speed (V) = \frac {2 \pi r}{t}

Where;

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Substituting into the formula, we have;

Circular \; speed (V) = \frac {2*3.142*2600}{360}

Circular \; speed (V) = \frac {16338.4}{360}

Circular speed, V = 45.38 m/s

Next, we find the centripetal acceleration;

Mathematically, centripetal acceleration is given by the formula;

Centripetal \; acceleration = \frac {V^{2}}{r}

Where;

  • V is the circular speed (velocity) of an object.
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Substituting into the formula, we have;

Centripetal \; acceleration = \frac {45.38^{2}}{2.6}

Centripetal \; acceleration = \frac {2059.34}{2600}

<em>Centripetal acceleration = 0.79 m/s²</em>

3 0
3 years ago
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