Answer:
Velocity of electron along x direction is 57.9 m/s
Explanation:
The uncertainty in x coordinate of electron, Δx = 0.200 mm = 0.2 x 10⁻³ m
Let vₓ be the x component of electrons velocity.
The uncertainty in x component of electrons momentum is:
Δpₓ = mΔvₓ
Here m is mass of the electron.
The uncertainty in velocity x component is 1% i.e. 0.01.
So, the above equation can be written as :
Δpₓ = 0.01mvₓ ....(1)
The minimum uncertainty principle is:
....(2)
Here h is Planck's constant.
From equation (1) and (2),

Substitute 0.2 x 10⁻³ m for Δx, 9.1 x 10⁻³¹ kg for m and 6.626 x 10⁻³⁴ m²kg/s in the above equation.

vₓ = 57.9 m/s
time to reach an angular velocity of 36.8 is 24.370 s.
<h3>
</h3><h3>What is angular acceleration?</h3>
The temporal rate at which angular velocity changes is referred to as angular acceleration. Naturally, there are two forms of angular acceleration, referred to as spin angular acceleration and orbital angular acceleration, just as there are two types of angular velocity, namely spin angular velocity and orbital angular velocity. As opposed to orbital angular acceleration, which is the angular acceleration of a point particle around a fixed origin, spin angular acceleration describes the angular acceleration of a rigid body about its centre of rotation.
w(t) = w(0) + α*t
also w(0) =0
=> time = 36.8/1.51= 24.370 s
to learn more about angular acceleration go to - brainly.com/question/21278452
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