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4 years ago

What is the voltage at the location of a 0.0001-coulomb charge that has an electric potential energy of 0.5 joules?

Physics

1 answer:

goldfiish [28.3K]4 years ago

6 0

Answer:

The voltage is 5000 V

Explanation:

Electric Potential energy: This can be defined as the energy or the work done i moving a charge against an electric field. The S.I unit of electric potential is Joules(J)

It can be represented mathematically as

W = VQ .................... Equation 1

V = W/Q................... Equation 2

Where W = Electric potential energy, V = voltage, Q = charge.

Given: W = 0.5 J, Q = 0.0001 C.

Substituting these values in into equation 2

V = 0.5/0.0001

V = 5000 V

Therefore the voltage is 5000 V

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A 78−kg skier is sliding down a ski slope at a constant velocity. The slope makes an angle of 21° above the horizontal direction

Feliz [49]

Answer:

274N 0.41

Explanation:

As he is sliding down in a constant speed then the force that accelerates him (weight) and the force that slows his down (friction) are equal.

then

friction=mass x gravity x sin(21)

Fr=78kg x 9.8m/s2 x sin(21)=274N

friction= coefficient of kinetic friction x normal force of from the slope

Fr= u x 78kg x 9.8m/s2 x cos(21)=274N

Fr= u x 78kg x 9.8m/s2 x cos(21)=274Nu=274/677=0.41

8 0

3 years ago

A projectile was fired horizontally from a cliff 20m above the ground. If

Montano1993 [528]

The initial velocity of the projectile is 19.8m/s

Explanation:

First, find time.

From our kinematics equations:

delta y = Vi•t + (1/2)at^2

rearrange,

t = sqrt[(2•delta y)/a]

t = sqrt[(2•20m)/9.8m/s^2]

t = 2.02s

Next, plug time into new kinematics equation to solve for the Vi in the x direction (horizontal)

delta x = Vi•t + (1/2)at^2

delta x = Vi•t

Rearrange:

Vi = delta x/t

Vi = 40m/2.02s

Vix = 19.8m/s

8 0

3 years ago

A commonly used unit of mass in the English system is the pound-mass, abbreviated lbm, where 1 lbm = 0.454 kg. What is the densi

Gemiola [76]

Answer: The density of glycerine will be $0.028lbm/foot^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given:

Density of glycerine= $1.26\times 10^3kg/m^3$

1 lbm = 0.454 kg

1 kg = $\frac{1}{0.454}=2.2lbm$

Thus $0.454kg=\frac{2.2}{1}\times 0.454=0.99$

Also $1m^3=35.3147foot^3$

Putting in the values we get:

$Density=\frac{0.99lbm}{35.3147}=0.028lbm/foot^3$

Thus density of glycerine will be $0.028lbm/foot^3$

3 0

3 years ago

A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every three days. It is not over that p

victus00 [196]

Answer: the radius of the satellite's orbit is r = 8.78×10⁷m

Explanation:

given the time period, T= 3days

converting the time in days to seconds is given as;

time, T=(3*24*60*60) sec

T=259200 sec

from the force relation;

mv²/r = Gm×M/r²

v²=G×M/r ---------------(1)

and

V=2pi×r/T

V²=4×pi²×r²/T²

====>

from equation (1) , we have

4×pi²×r²/T²=G×M/r

this becomes; 4×pi²×r³/T² = G×M

r³ = G×M×T²/(4pi²)

r³ = 6.67×10⁻¹¹×(5.97×10²⁴)×(259200)²/(4pi²)

==> r=8.78×10⁷m

radius of the orbit, r=8.78×10⁷ m

8 0

4 years ago

Integrate your expressions for dEx and dEy from θ=0 to θ=π. The results will be the x-component and y-component of the electric

Nimfa-mama [501]

Answer:

hello your question is incomplete below is the missing part

Ex = 0

Ey = $\frac{-2kQ}{\pi a^2}$

Explanation:

Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π

Ex = 0

Ey = $\frac{-2kQ}{\pi a^2}$

6 0

3 years ago