To answer this you must know that the acceleration caused by gravity upon the ball, or any object, is -9.8 m/s^2
there's two ways to solve this
first, use the position equation
x=(1/2)at^2+Vot+Xo
Xo, the initial position, is 3.5 m
x(t), the final position, is 0 m (the ground)
Vo, the initial velocity, is 0 m/s, since you just drop the ball
and a is -9.8
so
0=(1/2)(-9.8)t^2+3.5
-3.5=-4.9t^2
t^2=0.71
t=0.845
so it takes the ball 0.845 s to hit the ground
now, using the velocity equation, v=at+Vo,
v=(-9.8)(0.845)+0=-8.28 m/s
therefore, the speed of the ball is 8.28 m/s when it hits the ground
Answer:
![62.7 m/s^2](https://tex.z-dn.net/?f=62.7%20m%2Fs%5E2)
Explanation:
Assuming the dragster accelerates at constant rate, the equation that describes the distance travelled by the dragster after time t is
![d(t) = ut + \frac{1}{2}at^2](https://tex.z-dn.net/?f=d%28t%29%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where
u is the initial velocity
a is the acceleration
If we assume that the dragster starts from rest,
u = 0
And we also know that at t = 3.58 s, the distance covered is
d = 402 m
Solving the formula for a, we find the acceleration:
![d=\frac{1}{2}at^2\\a=\frac{2d}{t^2}=\frac{2(402)}{(3.58)^2}=62.7 m/s^2](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5Ca%3D%5Cfrac%7B2d%7D%7Bt%5E2%7D%3D%5Cfrac%7B2%28402%29%7D%7B%283.58%29%5E2%7D%3D62.7%20m%2Fs%5E2)
Answer:
The possibility of Adenine=40% and Thymine=60% is only in single stranded DNA molecule. In the question, the DNA sample referred is a single stranded DNA. If guanine=10% as guanine will always pair with cytosine, i.e.cytosine is also 10% then adenine and thymine accounts 80% as adenine will always pair with thymine.
Answer :
Population composition is the description of a,population according to characteristics such as age and sex . These data are often compared over time using population pyramids.