Answer:
a) 0.0048 T
b) 0.00093 T
c) 0 T
Explanation:
B = μ(0) [I - i'] / 2πr
where I = 24, and i' = 0, this means that
B = [12.568*10^-7 (24 - 0) ] / 2 * 3.142 * 0.001
B = 3.016*10^-5 / 0.006284
B = 0.0048 T
b), formula is the same, except for change in values, so we have
I = 24, and
i' = (3y2 - 2y2) / (4y2 - 2y2) * 24
i' = 10, and substituting these in the equation, we have
B = [12.568*10^-7 (24 - 10) ] / 2 * 3.142 * 0.003
B = (12.568*10^-7 * 14) / 0.018852
B = 1.76*10^-5 / 0.018852
B = 0.00093 T
and for the last one, we have
I = 24 and i' = 24 also, so that
B = [12.568*10^-7 (24 - 24) ] / 2 * 3.142 * 0.005
B = 0 / 0.03142
B = 0
