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kari74 [83]
3 years ago
11

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat

and 8 pieces of white meat costs 8.90. Find the cost of a piece of dark meat and the cost of a piece of white meat.
Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

Answer:

The cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be x.

And the cost of a piece of white meat be y.

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

4x+5y=7.05

4x=7.05-5y  

x=\frac{7.05-5y}{4}   .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

3x+8y=8.90

Substituting the value of x from equation (1) we get:

3(\frac{7.05-5y}{4})+8y=8.90

\frac{21.15-15y}{4} +8y=8.90

\frac{21.15-15y+32y}{4} =8.90

<em>Multiplying both sides by 4 we get:</em>

21.15-15y+32y=35.60

21.15+17y=35.60

<em>Subtracting both sides by 21.15 we get:</em>

17y=14.45

<em>Dividing both sides by 17 we get:</em>

y=0.85

<u>The cost of a piece of white meat = $0.85.</u>

Now, substituting the value of y in equation (1) we get:

x=\frac{7.05-5y}{4}

x=\frac{7.05-5\times 0.85}{4}

x=\frac{7.05-4.25}{4}

x=\frac{2.8}{4}

x=0.70.

<u>The cost of a piece of dark meat = $0.70.</u>

Therefore, the cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

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