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spin [16.1K]
3 years ago
10

Ionic bonds form between which two types of elements?​

Chemistry
2 answers:
lisabon 2012 [21]3 years ago
8 0

Answer:

metal and nonmetal ions

Explanation:

Alla [95]3 years ago
4 0

Answer:

Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.

Explanation:

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How many total electrons can be contained in the 4d sublevel? <br> 2<br> 6<br> 10<br> 14
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So, having this in mind, 10 electrons in total can be contained in the 4d sublevel.
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<em>It convert carbon monoxide faster </em>

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Benzene can be nitrated with a mixture of nitric and sulfuric acids. How do we do that?
Montano1993 [528]

Answer:

We can do the nitration of benzene by treating the benzene with a mixture of nitric acid and sulphuric acid by not extending the temperature of 50°C

Explanation:

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5 0
3 years ago
7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken
Nana76 [90]

<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution.  The equation used to calculate molarity of the solution is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M

Hence, the molarity of Iron (III) chloride is 0.622 M.

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3 years ago
What element would a metal, like sodium, most likely combine with?
OverLord2011 [107]
The answer you are looking for is "bromine". Hope this helps!
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