All categories

3 years ago

A parallel circuit contains ___________.

Physics

2 answers:

Roman55 [17]3 years ago

7 0

Your question is d and there u go

kotykmax [81]3 years ago

3 0

The answer to your question is D

You might be interested in

If you get a ticket for speeding, it is based on your average speed or instantaneous speed? Explain

bagirrra123 [75]

Answer:

Instantaneous speed

Explanation:

Usually the speed measuring guns are used to measure the speed at a certain instant, so the measured speed is instantaneous.

The average speed is determined by the expression final distance minus initial distance divided by time

$v_{aver} =\frac{x_{f}- x_{i}}{t}$

The instantaneous speed is determined in the same way as the average, but with the exception that the travel displacements are shorter (very close one each other).

5 0

3 years ago

1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?

antiseptic1488 [7]

Answer: 1. The movie one is virtual and the bathroom mirror is real

2. The image is distorted in a way

3. Behind the spoon

Explanation:

7 0

2 years ago

You are standing in a building whose height (40m) you throw a ball downward at a angle of -30 at a speed of (10m/s) acceleration

jeyben [28]

Answer: 3.41 s

Explanation:

Assuming the question is to find the time $t$ the ball is in air, we can use the following equation:

$y=y_{o}+V_{o}sin \theta t-\frac{1}{2}gt^{2}$

Where:

$y=0m$ is the final height of the ball

$y_{o}=40 m$ is the initial height of the ball

$V_{o}=10 m/s$ is the initial velocity of the ball

$t$ is the time the ball is in air

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$\theta=30\°$

Then:

$0 m=40 m+(10 m/s)(sin(30\°))t-\frac{1}{2}9.8 m/s^{2}t^{2}$

$0 m=40 m+5m/s t-4.9 m/s^{2}t^{2}$

Multiplying both sides of the equation by -1 and rearranging:

$4.9 m/s^{2}t^{2}-5m/s t-40 m=0$

At this point we have a quadratic equation of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

Where:

$a=4.9$

$b=-5$

$c=-40$

Substituting the known values:

$t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(4.9)(-40)}}{2(4.9)}$

Solving the equation and choosing the positive result we have:

$t=3.41 s$ This is the time the ball is in air

5 0

4 years ago

I need 4 answers for Earth's layers and 4 answers for the Descriptions for Earth's layers graphic organizer.

Arada [10]

Ok well have a nice day

3 0

3 years ago

In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively

Elanso [62]

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

8 0

3 years ago