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4 years ago

What factor is most important in determining whether water is a solid liquid or gas

Chemistry

2 answers:

Usimov [2.4K]4 years ago

6 0

Answer:

Temperature

Explanation:

temperatures below 0 degrees celsius will turn water into ice

Temperatures 1 to 99 degrees celsius is water in liquid form

Temperatures of over 100 degrees celsius liquid turns into gas

ExtremeBDS [4]4 years ago

3 0

Answer:

Temperature

Explanation:

Water is the most essential element that is required by all living organisms. This water on earth exists in all the three states, namely solid, liquid and gas. The temperature is the main factor that describes if a water is present in any of the three forms.

When water is heated at a temperature of 100°C, it evaporates and changes into water vapor. This is the gaseous state of water and this process of transformation of water from liquid to gaseous state is known as the evaporation process.

When water is frozen at a temperature of 0°C, then it freezes and forms ice. This is the solid state of water.

When water has a temperature between 0 to 100°C then , it exist in the state of liquid.

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natta225 [31]

Answer:

adding more water to the container

Explanation: because it would cause it to soak up the fluid to created a substance again

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3 years ago

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Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2

Usimov [2.4K]

Answer:

$\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 98.08 392.18

2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

Use the molar mass of H₂SO₄ to convert the mass of H₂SO₄ to moles of H₂SO₄
Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

$\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}$

(ii) Moles of H₂SO₄

$\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}$

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ $\text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}$

(iv) Mass of Cr₂(SO₄)₃ $\text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}$

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

$\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}$

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4 years ago

_____ is the breakdown of rock by natural forces and chemical changes. A. Erosion B. Weathering C. Crystallization D. Metamorphi

sp2606 [1]

Answer:

Weathering is the breakdown of rock by natural forces and chemical changes

Explanation:

The air and water (rain) are natural forces that breaks down rocks

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3 years ago

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Ill attach a picture

Anna [14]

Answer:

35.50

Explanation:

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3 years ago

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jeyben [28]

Noble Gases is the answer. These elements have a full outer shell composed of eight valence electrons, meaning that they do not need to gain electrons from other elements in reactions, making them nonreactive (inert).

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3 years ago

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