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3 years ago

What factor is most important in determining whether water is a solid liquid or gas

Chemistry

2 answers:

Usimov [2.4K]3 years ago

6 0

Answer:

Temperature

Explanation:

temperatures below 0 degrees celsius will turn water into ice

Temperatures 1 to 99 degrees celsius is water in liquid form

Temperatures of over 100 degrees celsius liquid turns into gas

ExtremeBDS [4]3 years ago

3 0

Answer:

Temperature

Explanation:

Water is the most essential element that is required by all living organisms. This water on earth exists in all the three states, namely solid, liquid and gas. The temperature is the main factor that describes if a water is present in any of the three forms.

When water is heated at a temperature of 100°C, it evaporates and changes into water vapor. This is the gaseous state of water and this process of transformation of water from liquid to gaseous state is known as the evaporation process.

When water is frozen at a temperature of 0°C, then it freezes and forms ice. This is the solid state of water.

When water has a temperature between 0 to 100°C then , it exist in the state of liquid.

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“Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil a

ANEK [815]

Well its Organic Chemistry... and is the Fractional Distillation of Crude Oil

3 0

3 years ago

When 2 moles of Fe(s) react with Cl2(g) to form FeCl3(s) according to the following equation, 799 kJ of energy are evolved.

GenaCL600 [577]

Answer:

1. Exothermic.

2. -1598 kJ.

Explanation:

Hello!

1. In this case, according to the reaction, we can infer that 799 kJ of energy are evolved (given off, released) it means that the enthalpy of reaction is negative as the reactants have more energy than the products; which means this is an exothermic reaction.

2. Here, as we know that the enthalpy of reaction is -799 kJ/mol, we can compute the q-value as shown below, considering the reacted 2 moles of solid iron:

$q=2mol*-799 kJ/mol\\\\q=-1598kJ$

Which means that 1598 kJ of energy are evolved when 2 moles of solid iron react.

Best regards!

4 0

3 years ago

Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79

BARSIC [14]

Answer : The mole fraction and partial pressure of $CH_4,CO_2$ and $He$ gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of $CH_4$ = 1.79 mole

Moles of $CO_2$ = 1.20 mole

Moles of $He$ = 3.71 mole

Now we have to calculate the mole fraction of $CH_4,CO_2$ and $He$ gases.

$\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267$

and,

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179$

and,

$\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554$

Thus, the mole fraction of $CH_4,CO_2$ and $He$ gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of $CH_4,CO_2$ and $He$ gases.

According to the Raoult's law,

$p_i=X_i\times p_T$

where,

$p_i$ = partial pressure of gas

$p_T$ = total pressure of gas = 5.78 atm

$X_i$ = mole fraction of gas

$p_{CH_4}=X_{CH_4}\times p_T$

$p_{CH_4}=0.267\times 5.78atm=1.54atm$

and,

$p_{CO_2}=X_{CO_2}\times p_T$

$p_{CO_2}=0.179\times 5.78atm=1.03atm$

and,

$p_{He}=X_{He}\times p_T$

$p_{He}=0.554\times 5.78atm=3.20atm$

Thus, the partial pressure of $CH_4,CO_2$ and $He$ gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0

3 years ago

What is the solubility of a solid in a solvent?

patriot [66]

Answer:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. ... The solvent is often a solid, which can be a pure substance or a mixture.

Explanation:

5 0

3 years ago

1.15.7 cm3 of HCl completely neutralised 25 cm3 of LiOH. The HCl was 2 mol/dm3.The equation is :

Whitepunk [10]

Answer:

C₂ = 1.26 mol/dm³

Explanation:

Given data:

Volume of HCl =V₁ = 15.7 cm³

Volume of LiOH = V₂ = 25 cm³

Concentration of HCl =C₁ = 2 mol/dm³

Concentration of LiOH =C₂= ?

Solution:

Chemical equation:

LiOH + HCl → LiCl + H₂O

Formula:

C₁V₁ = C₂V₂

by putting values,

15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³

C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³

C₂ = 31.4 cm₃.mol/dm³ / 25 cm³

C₂ = 1.26 mol/dm³

8 0

3 years ago