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3 years ago

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All biomes don’t have the same level of biodiversity. What seems to be the optimal conditions for high biodiversity?

1 answer:

irinina [24]3 years ago

6 0

Answer:

See the answer below

Explanation:

The optimal conditions for high biodiversity seem to be a <u>warm temperature</u> and <u>wet climates</u>.

<em>The tropical areas of the world have the highest biodiversity and are characterized by an average annual temperature of above 18 </em> $^oC$ <em> and annual precipitation of 262 cm. The areas are referred to as the world's biodiversity hotspots. </em>

Consequently, it follows logically that the optimal conditions for high biodiversity would be a warm temperature of above 18 $^oC$ and wet environment with annual precipitation of not less than 262 cm.

The variation in temperature and precipitation across biomes can thus be said to be responsible for the variation in the level of biodiversity in them.

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A force is acting on a 3-kg object during 5 seconds. If the object initially has a speed of 1.5m/s and after applying the force

uranmaximum [27]

Answer:

1.5 N

Explanation:

You've left us to guess what the question is. I will Assume it is what's the force?

Givens

m = 3 kg

vi = 1.5 m/s

vf = 4 m/s

t = 5 seconds

Formula

F = m * (vf - vi)/t

Solution

F = 3 * (4 - 1.5) / 5

F = 1.5 N

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2 years ago

Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book &am

stich3 [128]

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

$\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}$

$\frac{1}{Req45}=\frac{1}{5}+\frac{1}{4}$

$\frac{1}{Req45}=0.2+0.25=0.45\\ Req45=2.22$

Now, this equivalent Req45 is in series with R3, therefore:

$Req345=R3+Req45\\Req345=4+2.22\\Req345=6.22$

This Req345 is in parallel with R2, i.e

$Req2345=(R2^{-1}+Req345^{-1} )^{-1}\\ Req2345=(4^{-1}+6.22^{-1} )^{-1} \\Req2345=2.43$

Now this gets in series with R1:

$Req12345=R1+Req2345\\Req12345=9+2.43\\Req12345=11.43$

Now, the power delivered Ws is:

$Ws=Vs*I=\frac{Vs^{2}}{Req} \\Ws=\frac{10^{2} }{11.43} \\Ws=8.75 Watts$

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3 years ago

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Answer:

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lukranit [14]

Answer:

3.8 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

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