Answer:
2361.6N
Explanation:
Mass of player = 82kg
Velocity = 1.2m/s
Kinetic energy of player:
= 1/2mv²
= 1/2*82*1.2²
= 41x1.44
= 59.04J
Final kinetic energy = 0
Change in kinetic energy
|∆k| = |0-59.04|
= 59.04
Workdone by the feet = fd
d = 0.025
Fd = 59.04
F = 59.04/0.025
= 2361.6N
This is his average force.
The direction in which an electrical signal is carried in a typical multi-polar neuron is:
Dendrites, cell body, axon
Specialized projection of neurons are dendrites and axon. The central part of neuron is cell body. So, the electrical signal is carried in a direction that first dendrites carried the signal then it goes towards cell body and then to axon.
Answer:
The lifetime of the particle is
Explanation:
From the question we are told that
The average rest energy is
The intrinsic width is
The lifetime is mathematically represented as
Where h is the Planck's constant with a value of
substituting values
Answer:
331.7m/s
Explanation:
Given parameters:
Initial velocity = 100m/s
Acceleration = 50m/s²
Distance = 1km = 1000m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we have to apply the right motion equation shown below;
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Now insert the parameters and solve;
v² = 100² + (2 x 50 x 1000)
v² = 110000
v = √110000 = 331.7m/s