Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 Å. The atom is placed in a (a) simple cubic , (b) fcc, (c) bcc, and (d) diamond lattice. As- suming that nearest atoms are touching each other, what is the lattice constant of each lattice?
1 answer:
Answer:
(a) A =
(b)
(c)
(d)
Solution:
As per the question:
Radius of atom, r = 1.95
Now,
(a) For a simple cubic lattice, lattice constant A:
A = 2r
A =
(b) For body centered cubic lattice:
(c) For face centered cubic lattice:
(d) For diamond lattice:
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