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Bess [88]
3 years ago
14

In the problem below, what is the student showing?

Physics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

S<em>tudent showing the volume of cube</em>

                      V = a³

                       if a = 3 cm

  Then volume is a³ = 3 ×3 × 3

                                 = 27 cm³

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A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
4 years ago
An AC generator has an output rms voltage of 100.0 V at a frequency of 42.0 Hz. If the generator is connected across a 45.0-mH i
Rus_ich [418]

Answer:

(a) 11.8692‬ ohm

(b) 12.447 A

(c) 17.6 A

Explanation:

a)  inductive reactance Z = L Ω

    = L x 2π x F

    = 45.0 x 10⁻³ x 2(3.14) x 42

    = 11.8692‬ ohm

b) rms current

    = 100 / 8.034

    = 12.447 A

c) maximum current in the circuit

    = I eff x rac2

    = 12.447 x 1.414

    = 17.6 A

4 0
4 years ago
What is the speed of a bus that travels 250.0 km in 2.00 hours?
hram777 [196]
125 kmph

250=2
X=1

250/2= 125

5 0
3 years ago
What is the angle o in the triangle below? (Hint: Use an inverse trigonometric<br> function.)
Shalnov [3]

Answer:

D. 66.4

Explanation:

So this problem uses SOHCAHTOA or the three trig functions.

Specifically this uses cosine, because it has an adjacent and a hypotenuse.

First you would determine what to do on the calculator, and since the problem is saying so, use the inverse cosine button. This will give you a angle measure from the decimal.

On a calculator, type in cos^-1(6/15). I used 6/15 because cosine is adjacent over hypotenuse. This will give you 66.4, which is D on the answers.

5 0
4 years ago
One end of a piano wire is wrapped around a cylindrical tuning peg and the other end is fixed in place. The tuning peg is turned
liq [111]

Answer:

T = 3183 N

Explanation:

When the screw is turned by two turns then change in the length of the wire is given as

\Delta L = 2(2\pi r)

\Delta L = 4\pi r

\Delta L = 4(\pi)(1.0 mm)

\Delta L = 12.56 mm

now we know by the formula of Young's modulus

Y = \frac{T/A}{\Delta L/L}

so we have

T = \frac{AY \Delta L}{L}

T = \frac{\pi (0.55 \times 10^{-3})^2(2.0 \times 10^{11})(12.56 \times 10^{-3})}{0.75}

T = 3183 N

3 0
3 years ago
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