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Bess [88]
3 years ago
14

In the problem below, what is the student showing?

Physics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

S<em>tudent showing the volume of cube</em>

                      V = a³

                       if a = 3 cm

  Then volume is a³ = 3 ×3 × 3

                                 = 27 cm³

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FromTheMoon [43]

Answer:

kinetic energy

Explanation:

because it is at the top going down

7 0
3 years ago
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These four surfaces are opaque; that is they reflect or absorb certain rays of light determine the color
masya89 [10]
In the first figure, the surface absorbs all colors except for green light, which is reflected: so, the surface will appear as green to our eyes, because green is the only color which is reflected by that surface.

Similarly, in the  second figure, the surface absorbs all colors except for blue, and so the surface will appear blue to our eyes.

In the third figure, the surface absorbs all colors, so it will appear black to our eyes (because no colors are reflected, and black=absence of colors).

In the fourth figure, all colors are reflected: this means the surface will appear white to our eyes (white= sum of all colors).
4 0
4 years ago
(a) A 1.00-μF capacitor is connected to a 15.0-V battery. How much energy is stored in the capacitor? ________ μJ (b) Had the ca
gulaghasi [49]

Answer:

(a) E_{ c} = 112.5 \mu J

(b) E'_{ c} = 18 \mu J

Solution:

According to the question:

Capacitance, C = 1.00\mu F = 1.00\times 10^{- 6} F

Voltage of the battery, V_{b} = 15.0 V

(a)The Energy stored in the Capacitor is given by:

E_{c} = \frac{1}{2}CV_{b}^{2}

E_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 15.0^{2}

E_{ c} = 112.5 \mu J

(b) When the voltage of the battery is 6.00 V, the the energy stored in the capacitor is given by:

E'_{c} = \frac{1}{2}CV'_{b}^{2}

E'_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 6.0^{2}

E'_{ c} = 18 \mu J

6 0
4 years ago
2) Escribir en notación común
LenKa [72]

Answer:

c nLKDCnasndasjasndasjdnaslkjdnsakjdnasjdnaklsjdkjlasndjlkasndnjasdasd

Explanation:

7 0
3 years ago
TV broadcast antennas are the tallest artificial structures on Earth. In 1987, a 72.0 kg physicist placed himself and 400 kg of
lisov135 [29]

Answer: 190μm

Explanation:

Given the following :

Mass of physicist (m1)= 72kg

Mass of equipment(m2) = 400kg

Height of antenna (L) = 610m

Radius(r) = 0.150

Youngs modulus of steel = 2 × 10^11 Nm^-2

Recall the young's modulus(y) formula :

Y = stress / strain

Stress = force (F) / area(A)

Strain = extension(E) / length (L)

Y = (F/A) ÷ (E/L)

Y = F/A × L/E

Y = FL /AE

Y × AE = FL

E = FL / YA

Area(A) = πr^2

A = π × 0.150^2 = 0.070695m^2

Force (F) = mg

(400 + 72) × 9.8m/s^2 = 4625.6N

THEREFORE :

E = (4625.6 × 610) / (2 × 10^11 × 0.070695)

E = 2821616 / 0.14139 × 10^11

E = 2821616 / 14139000000

E = 0.00019956262819152

E = 0.0001995

E = 1.995 × 10^-4m = 199.5 × 10^-6

Approx E = 190μm

8 0
4 years ago
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