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quester [9]
3 years ago
15

What us probabilith​

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷Probability is the chance of getting something randomly.

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

TROLLER

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What does i^16 equal and how do you get the answer​
svp [43]

Answer:

i^16 = 1

Step-by-step explanation:

i = √-1 = i

i^2 = i * i = (√-1)^2 = -1

i^3 = i^2 * i^1 = -1 * √-1 = -√-1 or -i

i^4 = i^2 * i^2 = -1 * -1 = 1

the order keeps following......

i^16 = 1

since i^16 is same thing as i^4 * i^4

and we know i^4 = 1 so 1*1=1

7 0
3 years ago
What is the area of the polygon shown below? (in the image). A. 322 mm^2 B. 364 mm^2 C. 520 mm^2 D. 584 mm^2 Show all work pleas
Oksanka [162]

Answer:

A. 322 mm^2

Step-by-step explanation:

The area of the rectangle is 14 times 20

14 x 20 = 280

The area of the rectangle is 1/2 times 14 times 6

1/2(14)(6)=42

Finally add 280 and 42 and the answer is 322

4 0
3 years ago
Read 2 more answers
Sophia exchanged 1,000 US dollars for the south African currency. the exchange rate was 7.15 rand to $1.00.
mel-nik [20]
1 / 7.15 = 1000 / x......$ 1 to 7.15 rand = $ 1000 to x rand
cross multiply because this is a proportion
(1)(x) = (7.15)(1000)
x = 7150 <=== Sophia got 7150 rand
5 0
3 years ago
Find the values of x, y, and z
Advocard [28]
I support this answer it’s correct I see it ♥️
3 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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