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quester [9]
3 years ago
15

What us probabilith​

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷Probability is the chance of getting something randomly.

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

TROLLER

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Choose the right symbol: <,>,= a)3- ... -8 b) -4 ... 10 c) 0 ... -1 d) +3 ... 0 e) -5 ... -|-5|
Gre4nikov [31]

Answer:

-3 > -8

-4 < 10

0 > -1

-5 = -5

Step-by-step explanation:

one is bigger than the other hopes this helps

7 0
3 years ago
Can someone please help with this problem and explain. Please answer quickly, thx :) (picture included)
Anna007 [38]
Exponential laws
(x^{m})^{n}=x^{mn}
x^{\frac{m}{n}}=\sqrt[n]{x^{m}}

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)= \sqrt[3]{m^{1}}= \sqrt[3]{m}
3 0
3 years ago
Integrate sin^-1(x) dx<br><br> please explain how to do it aswell ...?
Lynna [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2264253

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}


Trigonometric substitution:

\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}


then,

\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}


So the integral \mathsf{(ii)} becomes

\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}


Integrate \mathsf{(ii)} by parts:

\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}

\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}


Substitute back for the variable x, and you get

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>

6 0
3 years ago
Provide reasons for the proof. <br> 40 points
antiseptic1488 [7]
Converse M^Q for # 3
converse M^VxP for #5
converse<_VxT ^ -M
6 0
3 years ago
Read 2 more answers
Does anyone please know the answer to this? Worth 30 points!!!
ch4aika [34]

Answer:

just graph the 2 points then do rise over run

Step-by-step explanation:

6 0
3 years ago
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