If a car has a velocity of 8 m/s and travels for 60 seconds, what was the displacement of the car?

yo this is due tomorrow help ya girl out : if a 2kg mass is accelerating at a rate of 2m/s^2 on a frictionless surface. how much

krok68 [10]

We Know, F = m.a
Here, m = 2 Kg
& a = 2 m/s²

Substitute for it,
F = 2*2 Kgm/s²
F = 4 Kgm/s²

8 0

4 years ago

How did J.J. Thomson's experiments demonstrate that Dalton's model of the atom was incorrect?

morpeh [17]

The correct option is C.
J.J Thompson demonstrated that Dalton's model of the atomic theory was wrong by showing that atoms are made up of sub particles, this is contrary to the report that Dalton gave about atoms. In his experiment, Dalton reported that atoms are indivisible, that is, they can not be broken down into smaller particles. J.J Thompson on the other was able to show through his cathode ray experiment that atoms are made up of smaller particles called electrons.

4 0

3 years ago

Read 2 more answers

Clarify the concept of refrection index with example

Degger [83]

The refractive index is used to measure how much light bends as it goes from one medium to another the refractive index of air =1 as light doesn’t bend in it

When looking into a glass of water with a straw the straw may appear bent or morphed as the water has a different refractive index to air (and the light is passing from air to glass of water)

3 0

3 years ago

Starting from one oasis, a camel walks 25 km in a direction 30° south of west and then walks 30 km toward the north to a second

shepuryov [24]

Answer:

distance between both oasis ( 1 and 2) is 27.83 Km

Explanation:

let d is the distance between oasis1 and oasis 2

from figure

OC = 25cos 30

OE = 25sin30

OE = CD

Therefore BC = 30-25sin30

distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem

in $\Delta BCO$

$OB^2 = BC^2 + OC^2$

PUTTING ALL VALUE IN ABOVE EQUATION

$d^2 = 930-25sin30)^2 + (25cos30)^2$

$d^2 = 775$

d = 27.83 Km

distance between both oasis ( 1 and 2) is 27.83 Km

3 0

3 years ago

an input force of 50 Newtons is applied through a distance of 10 meters to machine with mechanical advantage of 3. If the work o

gladu [14]

The output of the machine is

(output work) = (output force) x (distance)

450 N-m = (output force) x (3 meters)

Divide each side
by 3 meters: Output force = (450 N-m) / (3 m)

= 150 newtons .

With all the information given about the output work, we don't need
to know anything about the input work, or even the fact that we're
dealing with a machine.

It's comforting, though, to look back and notice that the output work
(450 N-m) is not more than the input work (500 N-m). So everything
is nice and hunky-dory.
___________________________________

Well, my goodness !
I didn't even need to go through all of that.

Given:

-- The input force to the machine is 50 newtons.

-- The mechanical advantage of the machine is 3 .

That right there tells us that

-- The output force of the machine is 150 newtons.

We don't need any of the other given information.

5 0

3 years ago