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victus00 [196]
3 years ago
6

What is a physical property of giant covalent structures?

Physics
2 answers:
yanalaym [24]3 years ago
7 0

Answer:

Very high melting points - Substances with giant covalent structures have very highmelting points, because a lot of strong covalent bonds must be broken. Graphite, for example, has a melting point of more than 3,600ºC. Variable conductivity - Diamond does not conduct electricity.

Explanation:

pav-90 [236]3 years ago
5 0
Very high melting<span> points - Substances with giant covalent structures have very high</span>melting<span> points, because a lot of strong covalent bonds must be broken. Graphite, for example, has a </span>melting point<span> of more than 3,600ºC. Variable conductivity - Diamond does not conduct electricity.</span>
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A 1,000 kg ball traveling at 5 m/s would have kinetic energy
MatroZZZ [7]

Answer:

12500 J = 12.5 kJ

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. =  (1/2)mv²

So you get, for ball

K.E. =  (1/2)×1000×5²  = 12500 J = 12.5 kJ

6 0
4 years ago
A motorist enters a freeway at 45 km/h and accelerates uniformly to 99 km/h. From the odometer in the car, the motorist knows th
Marat540 [252]

Answer:

a)  19440 km/h²

b) 10 sec

Explanation:

v₀ = initial velocity of the car = 45 km/h

v = final velocity achieved by the car = 99 km/h

d = distance traveled by the car while accelerating = 0.2 km

a = acceleration of the car

Using the kinematics equation

v² = v₀² + 2 a d

99² = 45² + 2 a (0.2)

a = 19440 km/h²

b)

t = time required to reach the final velocity

Using the kinematics equation

v = v₀ + a t

99 = 45 + (19440) t

t = 0.00278 h

t = 0.00278 x 3600 sec

t = 10 sec

5 0
3 years ago
A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro
mote1985 [20]

Answer: a_{2}=\frac{m_{1}}{m_{2}} a_{1}

Explanation:

The rest of the question is below:

Find a2, the magnitude of the centripetal acceleration of the star with mass m2.

Assuming both stars are describing a uniform circular motion, their acceleration vector is directed towards the center of mass of the system (that's why it's called centripetal acceleration).  

Now, according to Newton's 2nd law, the force F is directly proportional and in the same direction as the acceleration.

For m_{1}:

F_{1}=m_{1}a_{1}  

For m_{2}:

F_{2}=m_{2}a_{2}  

If the centripetal force is the same for both stars:

F_{1}=F_{2}  

m_{1}a_{1}=m_{2}a_{2}  

Isolating a_{2}:

a_{2}=\frac{m_{1}}{m_{2}} a_{1}

8 0
3 years ago
An object moves along the grid through the points A, B, C, D, E, and Fas shown below.
sveticcg [70]

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.

7 0
3 years ago
Does a black hole have 2 sides that pull light together?
Ostrovityanka [42]
Check this Light doesn't have mass or gravity right?
So if it doesn't have mass or gravity so light can only affect objects with mass
Does that make sense?
The black hole has gravity and remember light doesn't have gravity so does it affect the light?
To answer that yes, and since light doesn't have gravity it gets "pulled" into the black hole

I hope this helps you

8 0
3 years ago
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