Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.
Explanation: Please see the attachments below
T = 4.25 ms = 4 x 10⁻³ s, the time for rebound
v₁ = 25.5 m/s, the impacting velocty
v₂ = -19.5 m/s, the rebounding velocity (n the opposite directon)
The change in velocity is
v₂ - v₁ = - (25.5+19.5) = -45 m/s
The acceleration is
a = (-45 m/s)/(4 s) = -11.25 m/s²
The negative sign indicates that the final velocity is opposiye to the impact velocty.
Answer: The magnitude of the acceleration is 11.25 m/s²
Answer: 1.044 E -17 A
Explanation:
L =1.50m
A = 0.380mm = 3.8E- 7
Resistivity p =1.70 E-8
R =pl/A
R = 1.70 E-8 × 1.5/ 3.8 E-7
R = 6.71 E-16 ohms
V = IR
0.700 = I × 6.71 E-16
I =1.044E-17 A
Answer:
Half of its value prior to the initiation of the discharge
Explanation:
