Part 1) Finding x
Note the double tickmarks for segments XY and YZ. This indicates the segments are the same length, which leads to point Y being the midpoint of segment XZ.
Therefore, XZ is twice as long as XY
XZ = 2*( XY )
XZ = 2*( 2x-1 )
XZ = 4x - 2
We also know that XZ = 2(3x-4) = 6x-8. Let's equate 4x-2 and 6x-8 and solve for x
6x-8 = 4x-2
6x-4x = -2+8
2x = 6
x = 6/3
x = 3
<h3>Answer is 3</h3>
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Part 2) Finding the length of YZ
The resut of part 1 (x = 3) is plugged into the equation for XY to get
XY = 2*x-1
XY = 2*3-1
XY = 6-1
XY = 5
Segment XY is 5 units long. So is segment YZ as these two segments are the same length (aka congruent).
<h3>Answer: 5</h3>
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Part 3) Finding the length of segment XZ
The answer from the previous part was 5. This doules to 5*2 = 10
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A longer way to get the same answer is to plug x = 3 into the XZ equation and we get...
XZ = 2*(3x-4)
XZ = 2*(3*3-4)
XZ = 2*(9-4)
XZ = 2*5
XZ = 10
and we get the same answer
<h3>Answer: 10</h3>
Step-by-step explanation:
y=(x+5)(x-1)
y=-5 x=0
y=0. x=-5
y=0 x=1
now you got the points so graph will be like
When considering similar triangles, we need congruent angles and proportional sides.
Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.
"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.
"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).
"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.
To conclude, the first option is sufficient to prove similarity (AAA)
$30/2=$15.
She charges $15 for one hour
Therefore, she must charge $75 for 5 hours
I cant see it or else i would help sorry..
