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qwelly [4]
3 years ago
14

The formation of the iron(III) thiocyanate complex ion is an exothermic equilibrium system. For each change to the system, indic

ate how the concentration of each species in the chemical equation will change to reestablish equilibrium. An up arrow indicates an increase in concentration, a down arrow indicates a decrease in concentration, and leaving it blank means there is no change in the concentration.
Chemistry
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

This question appears incomplete

Explanation:

The equation for the formation of iron(III) thiocyanate complex ion is

Fe³⁺ + SCN⁻ ⇄ Fe(SCN)²⁺

Three factors affect the equilibrium of a reaction

  • temperature
  • pressure (in gases)
  • concentration

Since the formation of Fe(SCN)²⁺ is an exothermic reaction (delta H is negative); an increase in temperature will favor the backward reaction and more reactants will be produced. When the temperature is however reduced, the forward reaction will be favored and more products will be produced.

When the concentration of the reactants increases, the forward reaction is favored and hence more Fe(SCN)²⁺ is produced. However, when the concentration of Fe(SCN)²⁺ decreases, the backward reaction is favored and more reactants are produced.

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The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
svp [43]
Q: A
according to this formula, we can get the mole fraction of water (n):
P(solu) = n Pv(water)
when we have Pv(solu) = 22.8 and Pv(water) = 23.8 so by substitution:
22.8 = n * 23.8
n= 0.958
- we need to get the moles of glucose:
moles of water = 500 g(mass weight) / 18 (molar weight)= 27.7 mol
n = moles of water / ( moles of water + moles of glucose)
0.958   = 27.7 / ( 27.7+ moles of glucose)
0.958 moles of glucose + 26.5 = 27.7
0.968 moles of glucose = 1.2
moles of glucose = 1.253 mol
∴ the mass of glucose = no.of glucose moles x molar mass 
                                      = 1.253 x 180 = 225.5 g
Q: B
here we also need to get n (mole fraction of water )by using this formula:
Pv(solu) = n Pv(water)
when we have Pv(solu)=132 & Pv(water)=150 so, by substition:
132= n * 150
n = 0.88
so, mole fraction of solution = 1 - 0.88 = 0.12
and we can get after that the moles of water = (mass weight / molar mass)
- no.moles of water = 85 g / 18 g/mol = 4.7 moles
- total moles in solution = moles of water / moles fraction of water 
                                        = 4.7 / 0.88 = 5.34 moles 
∴ moles of the solution = total moles in solu - moles of water 
                                       = 5.34 - 4.7 = 0.64 moles solute
∴ the molar mass of the solute = mass weight of solute / no.of moles of solute
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Q: C

moles of urea (NH2)2 CO = mass weight / molar mass
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moles of methanol = mass weight / molar mass 
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moles fraction of methanol = moles of methanol / (moles of methanol + moles of urea )
moles fraction of methanol = 1.25 / ( 1.25+0.07) = 0.95
by substitution in Pv formula we will be able to get the vapour pressure of the solu :
Pv(solu) = n P°v
Pv(solu) = 0.95 * 89 mm Hg 
∴Pv(solu) = 84.55 mmHg


 
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Explanation:

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ground state

Mn=Ar3d⁵4s²

note that Ar is argon

3 0
2 years ago
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