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ololo11 [35]
3 years ago
5

Why is the periodic table such as useful tool for chemist?

Chemistry
1 answer:
Tomtit [17]3 years ago
3 0
The periodic table is useful tool for chemist since we can see what is the atomic and mass number for each atom.

Atomic number is equal to how many protons and electrons in it

Mass number is equal to protons + Neutrons.
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Using the ideal gas law, PV=nRT, where R=0.0821 L atm/mol K, calculate the volume in liters of oxygen produced by the catalytic
AfilCa [17]

Answer:

V = 2.32 Liters

Explanation:

PV = nRT => V = nRT/P

n = 25.8g/122g/mole = 0.21 mole

R = 0.08206 L·atm/mol·K

T = 25.44°C + 273 = 298.44K

P = 2.22 atm (given in problem)

V = (0.21mol)(0.08206 L·atm/mol·K)(298.44K)/(2.22atm) = 2.32 Liters at 25.44°C & 2.22atm

8 0
3 years ago
What is true about radioactive isotopes of an atom?
jenyasd209 [6]

Answer:

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Explanation:

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Which mixture is classified as a solution?
svlad2 [7]
Salt water is considered to be a solution
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3 years ago
What is the percent of copper in CuS?
bonufazy [111]

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Element Symbol Mass Percent

Cuprum Cu 66.464%

Sulfur S 33.537%

Explanation:

I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!

7 0
3 years ago
If 42.7 of 0.208 M hydrochloric acid are needed to completely neutralize a solution of calcium hydroxide, how many grams of calc
Montano1993 [528]

Answer:

0.329 g

Explanation:

In the context of this problem, we have a chemical reaction between hydrochloric acid and calcium hydroxide. HCl is the acid here and calcium hydroxide is the base. Hence, we have an acid-base reaction, also known as neutralization reaction.

In a neutralization reaction, water is produced as a product, as well as a salt that we obtain after we exchange the cations: calcium bonds to chloride and hydrogen bonds to hydroxide (the latter is the formation of water). This means we also produce calcium chloride as a product. The overall reaction represents this as:

Ca(OH)_2(aq)+2 HCl (aq)\rightarrow CaCl_2 (aq)+2 H_2O (l)

Firslt of all, we wish to find the number of moles of HCl present. Having molarity and volume, this is done by applying the molarity formula. It states that molarity is equal to the rate between moles and volume:

c_{HCl}=\frac{n_{HCl}}{V_{HCl}}

Rearranging for moles of HCl, n:

n_{HCl}=c_{HCl}V_{HCl}

Based on stoichiometry of the balanced chemical equation, notice that 1 mole of calcium hydroxide reacts with 2 moles of HCl, meaning:

n_{Ca(OH)_2}=\frac{1}{2} n_{HCl}=\frac{1}{2}c_{HCl}V_{HCl}

Now that we have the expression for moles, we may also express moles of calcium hydroxide as the ratio between its mass and molar mass:

n_{Ca(OH)_2}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}

Using the last two equations, we see that:

\frac{1}{2}c_{HCl}V_{HCl}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}\\\therefore m_{Ca(OH)_2}=\frac{1}{2}c_{HCl}V_{HCl}M_{Ca(OH)_2}

Substitute the given data, as well as the molar mass of calcium hydroxide:

m_{Ca(OH)_2}=\frac{1}{2}\cdot0.208 M\cdot0.0427 L\cdot74.093 g/mol=0.329 g

8 0
3 years ago
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