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ololo11 [35]
3 years ago
5

Why is the periodic table such as useful tool for chemist?

Chemistry
1 answer:
Tomtit [17]3 years ago
3 0
The periodic table is useful tool for chemist since we can see what is the atomic and mass number for each atom.

Atomic number is equal to how many protons and electrons in it

Mass number is equal to protons + Neutrons.
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The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close
Natasha_Volkova [10]

Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log(A^-/HA) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log(A^-/HA\\) and so 10 = A^-/HA or 10HA = A-.  For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

6 0
3 years ago
all of the following are physical properties of a substance in the in the liquid state except. A) definite volume B) Not easily
NARA [144]
<span> indefinite volume </span>

<span>If the mass is definite and the density is definite, </span>
<span>then your volume is definite.</span>
3 0
3 years ago
Read 2 more answers
Can someone help me with this question?
Softa [21]

Answer:

5 , I think. sorry if its wrong

8 0
3 years ago
The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
Which organism is the carnivore in this food web?
mihalych1998 [28]
Among the choices, the only one that can be considered a carnivore is C. Adelie penguin. Adelie penguins are found in the Arctic, and feed on aquatic creatures such as krill, fish, and squid. Krill is a type of crustacean that feeds on phytoplankton, which is at the bottom of the food chain.
8 0
3 years ago
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