Name the following compound: CH₂-CH-CH₂ - CH₂ - CH3 1 2 CH₂ CH₂

Is turning something anhydrous endo or exothermic?

seraphim [82]

It is endothermic because heat energy is supplied to make the water of crystallization evaporate and make the compound anhydrous.

3 0

3 years ago

3. Hydrochloric acid is used to clean metals.

ss7ja [257]

The answer to your question is option b, a base. This is because the question clearly tells you that one reactant is an acid. Then, it tells you that an acid plus something gives you a salt and water, as products

From background knowledge, we know that a base plus acid gives you a salt and water. The hydroxide ions from the base neutralise the hydrogen ions from the acid, which gives you water ( as it has a pH of 7).

Therefore, your answer is b, a base

4 0

3 years ago

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(1.) Using Beer's Law, How will the absorbance measured for the solutions change as the concentration of aspirin in solutions in

Vesnalui [34]

Answer:

(1) The absorbance of the aspirin in solutions will increase.

(2) [ASA]f = 3.79x10⁻⁴M

(3) [ASA]i = 3.79x10⁻³M

(4) m ASA = 0.171g

Explanation:

The Beer's Law is expressed by:

$A = \epsilon \cdot l \cdot C$ (1)

where A: is the absorbance of the species, ε: is the molar attenuation coefficient, l: is the pathlength and C: is the concentration of the species

(1) From equation (1), the relation between the absorbance of the species and its concentration is directly proportional, so if the aspirin concentration in solutions increases, the absorbance of the solutions will also increase.

(2) Starting in the given expression for the relationship between absorbance and concentration of ASA, we can calculate its concentration in the solution:

$A = 1061.5 \cdot [ASA]$

$[ASA] = \frac{A}{1061.5} = 3.79 \cdot 10^{-4}M$

Therefore, the aspirin concentration in the solution is 3.79x10⁻⁴ M

(3) To calculate the stock solution concentration, we can use the next equation:

$V_{i} [ASA]_{i} = V_{f} [ASA]_{f}$

where Vi: is the stock solution volume=10mL, Vf: is the solution diluted volume=100mL, [ASA]i: is the aspirin concentration of the stock solution and [ASA]f: is the aspirin concentration of the diluted solution

$[ASA]_{i} = \frac{V_{f} \cdot [ASA]_{f}}{V_{i}} = \frac {100mL \cdot 3.79\cdot 10^{-4} M}{10mL} = 3.79 \cdot 10^{-3} M$

Hence, the concentration of the stock solution is 3.79x10⁻³M

(4) To determine the aspirin mass in the tablet, we need to use the following equation:

$m_{ASA} = \eta_{ASA} \cdot M_{ASA} = [ASA]_{i} \cdot V_{0} \cdot M_{ASA}$

where η: is the aspirin moles = [ASA]i V₀, M: is the molar mass of aspirin=180.158g/mol, V₀: is the volume of the volumetric flask=250mL and [ASA]i: is the aspirin concentration in the volumetric flask which is equal to the stock solution=3.79x10⁻³M

$m_{ASA} = 3.79 \cdot 10^{-3} \frac{mol}{L} \cdot 0.250L \cdot 180.158 \frac{g}{mol} = 0.171 g$

Then, the aspirin mass in the tablet is 0.171 g.

I hope it helps you!

5 0

3 years ago

Which of the following compounds exhibit hydrogen bonding?

hodyreva [135]

Answer:

a,b,e,f,g

Explanation:

Hydrogen bonding is an intermolecular force of attraction between two molecules. It is a special type of dipole-dipole attraction.

In hydrogen bonding, the hydrogen on one molecule binds with an electronegative atom on another molecule usually oxygen, nitrogen and fluorine.

The simple electrostatic attraction leads to strong intermolecular interaction between two molecules.

For the formation of hydrogen bond, a hydrogen atom must be bonded to more electronegative specie usually N, O and F

In H₂O and H₂O₂ ; hydrogen bonds with Oxygen

CH₃NH₂; hydrogen is attached to nitrogen

HF; hydrogen is attached to fluorine

CH₃OH; hydrogen is attached to oxygen

7 0

3 years ago

A car is traveling with an initial velocity of 15 m/s when the driver decides to go faster by accelerating at 5 m/s2 for 10 seco

Ilia_Sergeevich [38]

Answer: Time needed: 2.5 s

Distance covered: 31.3 m

Explanation:

I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by

on one side of the equation and solve by plugging your values

To get the time needed to reach this speed, i.e. 10.0 m/s, you can use the following equation

Explanation:

7 0

3 years ago