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3 years ago

Fun fact! <3

Chemistry

2 answers:

aleksklad [387]3 years ago

7 0

✧ Yes, since one of our senses are missing we won't really detect the taste.

Explanation: Think about it, we usually smell food and we can already tell if it's going to taste good or not. Looking or touching food doesn't always help to know if we will like the taste. ✧

victus00 [196]3 years ago

3 0

Answer:

:O Fr? Bet let me go get them lol

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Fran hangs three balloons from strings. She gives the first balloon a positive charge. She gives the second balloon a negative c

fgiga [73]

Explanation: We are given three balloon carrying different charges: One having positive charge, one having negative charge and one having no charge.

When we bring positive rod near these three balloons, all of them behave differently.

According to the Coulomb's Law:

Like charges repel each other and unlike charges attract each other.

When we bring positive rod towards the balloon having positive charge, the balloon will move away from the rod, because like charges repel each other.

When we bring positive rod near negative balloon, the balloon will be attracted to the rod because unlike charges attract each other.

But, when we bring positive rod towards the balloon having no charge, the charges will be induced in the balloon. Although the balloon is neutral in nature but it will still carry some +ve or -ve charges. So, when the positive rod is bought near neutral ball, the negative side of the balloon will get attracted towards the rod and positive side will be repelled. From this, we say that the rod has induced some charges in the balloon.

5 0

3 years ago

A first-order reaction has a half-life of 29.2 s . how long does it take for the concentration of the reactant in the reaction t

Dmitriy789 [7]

Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value

The half-life for the chemical reaction is 29,2 s and is independent of initial concentration.
c₀ - initial concentration the reactant.

c - concentration of the reactant remaining at time.

t = 29,2 s.
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s = 0,0237 1/s.
ln(c/c₀) = -k·t₁.
ln(1/16 ÷ 1) = -0,0237 1/s · t₁.

t₁ = 116,8 s.

5 0

3 years ago

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4 What volume of 1.45 M Ca(OH)2 is needed to react with 25.0 moles of H2SO4?

Shkiper50 [21]

Answer:

We need 17.2 L of Ca(OH)2

Explanation:

Step 1: Data given

Concentration of Ca(OH)2 = 1.45 M

Moles of H2SO4 = 25.0 moles

Step 2: The balanced equation

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4

Step 3: Calculate moles Ca(OH)2

For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4

For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4

Step 4: Calculate volume of Ca(OH)2

Volume Ca(OH)2 = moles Ca(OH)2 / concentration Ca(OH)2

Volume Ca(OH)2 = 25.0 moles / 1.45 M

Volume Ca(OH)2 = 17.2 L

We need 17.2 L of Ca(OH)2

3 0

3 years ago

Which two particles are found in the nucleus of an atom?

choli [55]

Protons and neutrons are found inside the nucleus

6 0

3 years ago

Read 2 more answers

A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24

Setler79 [48]

Answer:

For Part A: The partial pressure of Helium is 218 mmHg.

For Part B: The mass of helium gas is 0.504 g.

Explanation:

For Part A:

We are given:

$p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg$

To calculate the partial pressure of helium, we use the formula:

$P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}$

Putting values in above equation, we get:

$745=245+119+163+p_{He}\\p_{He}=218mmHg$

Hence, the partial pressure of Helium is 218 mmHg.

For Part B:

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

$PV=\frac{m}{M}RT$

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

$218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g$

Hence, the mass of helium gas is 0.504 g.

6 0

3 years ago