1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
14

What is the momentum of a vehicle that has a mass of 1500kg and a velocity of 15m/s? (don't forget the unit is kg*m/s, and needs

to be written just like that) *
Physics
1 answer:
alex41 [277]3 years ago
4 0

Answer:

<h2>22500 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 1500 × 15

We have the final answer as

<h3>22500 kg.m/s</h3>

Hope this helps you

You might be interested in
What is the measurement of six centimeters equal to?
AlladinOne [14]
Six centimeters equal to about two inches
8 0
3 years ago
Find p1, the gauge pressure at the bottom of tube 1. (Gauge pressure is the pressure in excess of outside atmospheric pressure.)
Taya2010 [7]

Answer:

(a). The gauge pressure at the bottom of tube 1 is P_{1}=\rho g h_{1}

(b).  The speed of the fluid in the left end of the main pipe \sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}

Explanation:

Given that,

Gauge pressure at bottom = p₁

Suppose, an arrangement with a horizontal pipe carrying fluid of density p . The fluid rises to heights h1 and h2 in the two open-ended tubes (see figure). The cross-sectional area of the pipe is A1 at the position of tube 1, and A2 at the position of tube 2.

Find the speed of the fluid in the left end of the main pipe.

(a). We need to calculate the gauge pressure at the bottom of tube 1

Using bernoulli equation

P_{1}=\rho g h_{1}

(b). We need to calculate the speed of the fluid in the left end of the main pipe

Using bernoulli equation

Pressure for first pipe,

P_{1}=\rho gh_{1}.....(I)

Pressure for second pipe,

P_{2}=\rho gh_{2}.....(II)

From equation (I) and (II)

P_{2}-P_{1}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)

Put the value of P₁ and P₂

\rho g h_{2}-\rho g h_{1}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)

gh_{2}-gh_{1}=\dfrac{1}{2}(v_{1}^2-v_{2}^2)

2g(h_{2}-h_{1})=v_{1}^2-v_{2}^2....(III)

We know that,

The continuity equation

v_{1}A_{1}=v_{2}A_{2}

v_{2}=v_{1}(\dfrac{A_{1}}{A_{2}})

Put the value of v₂ in equation (III)

2g(h_{2}-h_{1})=v_{1}^2-(v_{1}(\dfrac{A_{1}}{A_{2}}))^2

2g(h_{2}-h_{1})=v_{1}^2(1-(\dfrac{A_{1}}{A_{2}}))^2

Here, \dfrac{A_{1}}{A_{2}}=\gamma

So, 2g(h_{2}-h_{1})=v_{1}^2(1-(\gamma)^2)

v_{1}=\sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}

Hence, (a). The gauge pressure at the bottom of tube 1 is P_{1}=\rho g h_{1}

(b).  The speed of the fluid in the left end of the main pipe \sqrt{\dfrac{2g(h_{2}-h_{1})}{(1-(\gamma)^2)}}

8 0
3 years ago
What is the most commonly used method of food preservation today? refrigeration drying foods smoking raw meats salt curing
dmitriy555 [2]
Refrigerator was what is commonly used today. We do dry foods and salt cure but that is not done on a daily basis
6 0
4 years ago
Read 2 more answers
A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the ca
Leona [35]

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

F=ma

a=\dfrac{F}{m}

a=\dfrac{901}{1423}

a=0.63\ m/s^2

Let v is the final speed of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

v^2=2ad+u^2

v^2=2\times 0.63\times 106+(26.4)^2

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

5 0
4 years ago
A lightbulb is rated to how a power output of 80 w, if the lightbulb is running for 600 seconds, how much energy (work) is it us
enyata [817]

Answer:

Light bulbs are rated in watts to indicate how much energy they consume. Does the wattage of a light bulb have anything to do with brightness? ... In general, that works well with traditional incandescent light bulbs. ... It's also worth noting that kW can be synonymous with “demand” if you're talking to a utility ...

Explanation:

Light bulbs are rated in watts to indicate how much energy they consume. Does the wattage of a light bulb have anything to do with brightness? ... In general, that works well with traditional incandescent light bulbs. ... It's also worth noting that kW can be synonymous with “demand” if you're talking to a utility ...

5 0
3 years ago
Other questions:
  • What forces shape the stars in galaxies? (Astronomy question, but didn't fit into any categories) PLEASE 
    6·1 answer
  • A small rock is thrown vertically upward with a speed of 22.0 m/s from the edge of the roof of a 30.0-m-tall building. The rock
    6·1 answer
  • The angular position of a point on the rim of a rotating wheel is given by θ(t) = 4.0t - 3.0t2 + t3, where θ is in radians and t
    9·1 answer
  • Can somebody help me on finding the constants if this experiment?
    8·1 answer
  • What is 0.40 as a fraction?
    12·2 answers
  • A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from wh
    5·1 answer
  • How much total heat transfer is necessary to lower the temperature of 0.175 kg of steam from 125.5 °C to −19.5 °C, including the
    14·1 answer
  • A solar heating system has a 25.0% conversion efficiency; the solar radiation incident on the panels is 1 000 W/m2.
    10·1 answer
  • The entire electromagnetic spectrum can be divided into seven bands: radio, microwave, infrared, visible, ultraviolet, X ray, an
    15·1 answer
  • A 5.0-kg centrifuge takes 95 s to spin up from rest to its final angular speed with constant angular acceleration. A point locat
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!