Explanation:
<em>carbon </em><em>in</em><em> </em><em>blanks</em><em> </em><em>I </em><em>think</em><em> </em><em>so</em><em> </em>
<em>PlZzzzz</em><em> </em><em>help</em><em> </em><em>me</em><em> </em><em>and</em><em> </em><em>mark</em><em> </em><em>as</em><em> </em><em>brainlist</em><em> PlZzzzz</em>
shes your teacher duh, they have magic spells that give em the answer
The molar concentration of NaOH can find out from the molarity of the titrant HCl. The molarity of NaOH is found to be 0.038 molar.
What is molarity?
Molarity is the number of moles of solute per volume of solution in liters. Here, the HCl has the density of 0.7292 g/l and volume 20L . Its mass is calculated as:
mass = density × volume
= 0.7292× 20L
= 14.58.
The molar mass of HCl is 37.5. Thus its number of moles in the solution is 14.58/37.5 = 0.388.
At the end point the number of moles of NaOH and HCl will be equal thus, where the volume of the NaOH solution is 10 ml. Now the molarity can be find out as follows:
molarity = number of moles /volume
= 0.388/10 = 0.038 M.
Hence, the molarity of HCl is 0.038 M.
To find more on molarity, refer here:
brainly.com/question/2817451
#SPJ1
Answer:
e. BaSO4 and KCI.
Explanation:
Hello there!
In this case, given the reactants side:
It is possible to realize that after the reaction takes place barium replaces potassium and therefore barium sulfate and potassium chloride are formed:
Therefore, the products turn out to be e. BaSO4 and KCI.
Best regards!
The question is incomplete; the complete question is;
What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S? Write the condensed structural formula (CH3)2C=O and CH3-CH2-CH=O
Answer:
2-methylpent-2-ene (C6H12)
Explanation:
Ozonolysis is a wonderful method for determining the location of double bonds in an alkene since the oxygenated carbons in the carbonyl compounds formed after ozonolysis are the ones that were initially joined by the double bonds in the original alkene.
Hence if an alkene yields (CH3)2C=O and CH3-CH2-CH=O, the original alkene must be C6H12, that is, 2-methylpent-2-ene