Based on experiment 1:
Mass of Hg = 1.00 g
Mass of sulfide = 1.16 g
Mass of sulfur = 1.16 - 1.00 = 0.16 g
# moles of Hg = 1 g/200 gmol-1 = 0.005 moles
# moles of S = 0.16/32 gmol-1 = 0.005 moles
The Hg:S ratio is 1:1, hence the sulfide is HgS
Based on experiment 2:
Mass of Hg taken = 1.56 g
# moles of Hg = 1.56/200 = 0.0078
Mass of S taken = 1.02 g
# moles of S = 1.02/32 = 0.0319
Hence the limiting reagent is Hg
# moles of Hg reacted = # moles of HgS formed = 0.0078 moles
Molar mass of HgS = 232 g/mol
Therefore, mass of HgS formed = 0.0078 * 232 = 1.809 g = 1.81 g
Answer: True
Explanation:
Let's begin by explaining that the vision phenomenon depends on three elements: the observer, the object and the light source.
In addition, objects have pigments, which generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.
In this sense, the colours we see are in fact the wavelengths that are reflected or transmitted from the object. For example, a red object has that color because when it is illuminated whith white light, the pigments on this object abrsorb all the the wavelengths of the visible electromagnetic spectrum, except red. That is why red light is the only light that is reflected from the mentioned object.
<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 
<u>Explanation:</u>
We are given:
Moles of copper(II) phosphate 
= 7.00 mol
1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms
Moles of phosphorus in copper(II) phosphate = 
According to the mole concept:
1 mole of a compound contains 
number of particles
So, 7.00 moles of copper(II) phosphate will contain = 
number of phosphorus atoms.
Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is
Answer:
393.1 KPa
Explanation:
Now we have to use the general gas equation;
P1V1/T1 = P2V2/T2
P1= initial pressure of the gas= 1.00atm
V1 = initial volume= 700.0 ml
T1= initial temperature= 0.0°C +273= 273K
V2= final volume= 200.0 ml
T2= final temperature =30.0°C +273= 303 K
P2= final pressure =????
Therefore;
P2= P1V1T2/ V2T1
P2= 1.00 × 700.0 × 303/ 200.0 × 273
P2= 3.88 atm
But
1 atm = 101.325 kilopascals
Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa
