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hram777 [196]
3 years ago
15

A sample of nitrogen occupies 10.0 liters at 25°c and 98.7 kpa. What would be the volume at 20°c and 102.7 kpa?

Chemistry
1 answer:
Fynjy0 [20]3 years ago
5 0

Answer:

  •    9.4 liter

Explanation:

<u>1) Data:</u>

  •  V₁ = 10.0 L
  •  T₁ = 25°C = 25 + 273.15 K = 298.15 K
  •   P₁ = 98.7 Kpa
  •   T₂ = 20°C = 20 + 273.15 K = 293.15 K
  •    P₂ = 102.7 KPa
  •    V₂ = ?

<u>2) Formula:</u>

Used combined law of gases:

  •    PV / T = constant

  •    P₁V₁ / T₁ = P₂V₂ / T₂

<u>3) Solution</u>:

Solve the equation for V₂:

  •    V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

  • V₂ = P₁V₁ T₂ / (P₂ T₁)

  • V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

  • V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on Brainly: brainly.com/question/12732788.

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Answer:

a)  T_b=590.775k

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Explanation:

From the question we are told that:

Moles of N2 n=2.50

Atmospheric pressure P=100atm

Temperature t=20 \textdegree C

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a)

Generally the equation for change in temperature is mathematically given by

\triangle T=\frac{Q}{N*C_v}

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Generally the equation for ideal gas is mathematically given by

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For v double

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Generally the equation for amount of heat added is mathematically given by

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Q=2.20*2907*(1181.55-590.775)\\

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Generally the equation for change in internal energy of the gas is mathematically given by

\triangle V=nC_v \triangle T

\triangle V=2.20*20.76*(1181.55-293)k

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The formula for the calculation of moles is shown below:

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