Draw the structural formula of (3e,5e)-2,5-dibromo-3,5-octadiene.
1 answer:
We need draw the structure of (3E,5E)-2,5-dibromo-3,5-octadiene.
The structure is shown below:
The molecule has two double bonds in 3 and 5 position and two Br-atoms attached to 2 and 5 position.
The configuration is 3E and 5E. E configuration indicates cis- isomers where similar groups are in same side with respect to double bonds.
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Answer: Linear
Explaination: The central atom of a carbon dioxide molecule is carbon. Carbon is tetravalent which just means it has 4 valence electrons. Because the valence shell isn’t full, the carbon atom can bond with other atoms creating a total of 4 bonds. This then allows the carbon to double bond with 2 oxygen atoms. Now, the atoms in the CO2 molecule Don’t share the electrons evenly because of atomic number or proton count. Because oxygen has an atomic number of 6, carbon has an atomic number of 4, and opposites attract (referring to the positivity of the nucleus and the negativity of the shared electrons), the oxygen atoms will have a slightly negative charge (-) and the oxygen will have a slightly positive charge (+ ). Therefore, the slightly negative oxygen atoms repel creating that linear shape.
Explaination: The central atom of a carbon dioxide molecule is carbon. Carbon is tetravalent which just means it has 4 valence electrons. Because the valence shell isn’t full, the carbon atom can bond with other atoms creating a total of 4 bonds. This then allows the carbon to double bond with 2 oxygen atoms. Now, the atoms in the CO2 molecule Don’t share the electrons evenly because of atomic number or proton count. Because oxygen has an atomic number of 6, carbon has an atomic number of 4, and opposites attract (referring to the positivity of the nucleus and the negativity of the shared electrons), the oxygen atoms will have a slightly negative charge (-) and the oxygen will have a slightly positive charge (+ ). Therefore, the slightly negative oxygen atoms repel creating that linear shape.