Draw the structural formula of (3e,5e)-2,5-dibromo-3,5-octadiene.
1 answer:
We need draw the structure of (3E,5E)-2,5-dibromo-3,5-octadiene.
The structure is shown below:
The molecule has two double bonds in 3 and 5 position and two Br-atoms attached to 2 and 5 position.
The configuration is 3E and 5E. E configuration indicates cis- isomers where similar groups are in same side with respect to double bonds.
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Answer : The oxidation number of chlorine (Cl) is, (+1)
Explanation :
Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
Rules for Oxidation Numbers :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is,
Let the oxidation state of 'Cl' be, 'x'
Therefore, the oxidation number of chlorine (Cl) is, (+1)