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mihalych1998 [28]
3 years ago
11

Identify the number of elements and the number of atoms present in the chemical formula.

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0
How do you know how many atoms are in a chemical formula?

~~~~~~~~~~~
in the formula. It also represents the number of molecules of that compound. has 4 sodium atoms, 2 sulphur atoms, and 8 oxygen atoms. When you count atoms, remember to multiply the coefficient number and the subscript number to find the number of atoms of that element.
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hichkok12 [17]

Answer: B

Explanation: I answered randomly

5 0
3 years ago
How many sulfur atoms are in 0.45 mol BaSO4??
Lemur [1.5K]

(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}

4 0
3 years ago
Read 2 more answers
How much energy is required to heat 2kg of ice from -5°c to 0°c
balu736 [363]

Explanation:

total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.

Heat=mhfg+mCpΔT

Here, m ( mass of ice) = 2 kg

hfg (latent heat of fusion of ice) = 334 KJ

Cp of water (specific heat) = 4.187 KJ/Kg-K

ΔT(Temperature difference) = 20 °C

Therefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )

Heat reqd= 835.48 KJ

Therefore, to melt 2 kg of ice 835.48 KJ of heat is required.

4 0
3 years ago
Attached are two chemistry questions I need help with. thank you to whoever helps me out
ivann1987 [24]
13.6 
a) yes Pb is more reactive  that Ag, Pb before Ag
b) no, Cu after H
c) yes, Cl2 is more active than I2
4) yes, Mg is more active

13.7 (as I think)
Al ³⁺  more active than Zn²⁺, Mn can react with  Zn²⁺, but not with Al ³⁺ , because Mn after Al but before Zn
4 0
3 years ago
The relative atomic mass of Chlorine is 35.45. Calculate the percentage abundance of the two isotopes of Chlorine, 35Cl and 37Cl
nata0808 [166]

Answer:

35Cl = 75.9 %

37Cl = 24.1 %

Explanation:

Step 1: Data given

The relative atomic mass of Chlorine = 35.45 amu

Mass of the isotopes:

35Cl = 34.96885269 amu

37Cl = 36.96590258 amu

Step 2: Calculate percentage abundance

35.45 = x*34.96885269 + y*36.96590258

x+y = 1  x = 1-y

35.45 = (1-y)*34.96885269 + y*36.96590258

35.45 = 34.96885269 - 34.96885269y +36.96590258y

0.48114731 = 1,99704989‬y

y = 0.241 = 24.1 %

35Cl = 34.96885269 amu = 75.9 %

37Cl = 36.96590258 amu = 24.1 %

3 0
3 years ago
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