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3 years ago

Whats photosynthesis

1 answer:

4 0

It is a process of a plant taking in sun rays and changing it into glucose ur sugar
The formula for this process is :
6CO_2 + 6H_2O -----> C6H12O6+6O_2

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What is the name of this molecule? h3c-c=c-ch3

Mamont248 [21]

Answer : The name of the given molecule is 2-butene or but-2-ene

Explanation :

Step 1 : Find the longest carbon chain.

The longest carbon chain for the given structure contains 4 carbons.

This will help us to find out the prefix for our parent compound.

The alkane with 4 carbons is "Butane"

Therefore our parent compound will have the prefix is "but"

Step 2 : Find the functional group

The functional group is the group that gives specific characteristics to the compound. In this case, we have a double bond in the structure which behaves as a functional group.

Therefore the functional group here is "Alkene"

Functional groups helps us to find the suffix of the name. In this case it is "ene"

Therefore our parent compound is but+ene = butene

Step 3 : Find the position of the double bond

The double bond is present between second and third carbon atom.

We always select the lower number to denote the position of the bond.

So we have 2-butene OR but-2-ene

There are no substituents present in this compound.

Therefore the name of the compound is 2-butene or But-2-ene

8 0

3 years ago

Read 2 more answers

Order the follow processes from (1) the least work done by the system to (5) the most work done by one mole of an ideal gas at 2

quester [9]

Answer : The order of process from (1) the least work done by the system to (5) the most work done by the system will be:

(1) < (5) < (3) < (4) < (2)

Explanation :

<u>The formula used for isothermally irreversible expansion is :</u>

$w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)$

where,

w = work done

$p_{ext}$ = external pressure

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

<u>The expression used for work done in reversible isothermal expansion will be,</u>

$w=-nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = ?

n = number of moles of gas = 1 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = $25^oC=273+25=298K$

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

First we have to determine the work done for the following process.

(1) An isothermal expansion from 1 L to 10 L at an external pressure of 2.5 atm.

$w=-p_{ext}(V_2-V_1)$

$w=-(2.5atm)\times (10-1)L$

$w=-22.5L.atm=-22.5\times 101.3J=-2279.25J$

(2) A free isothermal expansion from 1 L to 100 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{100L}{1L})$

$w=-11409.6J$

(3) A reversible isothermal expansion from 0.5 L to 4 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{4L}{0.5L})$

$w=-5151.97J$

(4) A reversible isothermal expansion from 0.5 L to 40 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{40L}{0.5L})$

$w=-10856.8J$

(5) An isothermal expansion from 1 L to 100 L at an external pressure of 0.5 atm.

$w=-p_{ext}(V_2-V_1)$

$w=-(0.5atm)\times (100-1)L$

$w=-49.5L.atm=-49.5\times 101.3J=-5014.35J$

Thus, the order of process from (1) the least work done by the system to (5) the most work done by the system will be:

(1) < (5) < (3) < (4) < (2)

8 0

3 years ago

The reaction below shows how silver chloride can be synthesized. AgNO3 NaCl Right arrow. NaNO3 AgCl How many moles of silver chl

Otrada [13]

From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

The balanced chemical reaction for the synthesis of silver chloride has been:

$\rm AgNO_3\;+\;NaCl\;\rightarrow\;AgCl\;+\;NaNO_3$

From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.