Answer:
Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
Explanation:
<span>The speed that reactants are converted into products is Reaction Rate. Reaction Rates describe slow reactions like rusting of an iron bar or fast reactions like combustion of gasoline in a car engine. This is extensively studied in the field of Chemical k</span>
Answer:
Fc = 89.67N
Explanation:
Since the rope is unstretchable, the total length will always be 34m.
From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:
L1+L2=34m
Replacing this value in the previous equation:
Solving for H:
We can now, calculate the angle between L1 and the 2m segment:
If we make a sum of forces in the midpoint of the rope we get:
where T is the tension on the rope and F is the exerted force of 87N.
Solving for T, we get the tension on the rope which is equal to the force exerted on the car:
Answer:
1900 metres
Explanation:
Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.
The parameters to be considered are:
Speed = 30 m/s
Time = 30 seconds
Speed = distance/time
Substitute the parameters into the formula
30 = distance / 30
Cross multiply
Distance = 30 × 30
Distance = 900 m
Since the train started from a position of 1000 m , the final position will be:
Final position = 1000 + 900
Final position = 1900 metres
<span>We know that an object in moving with acceleration follow the rule according that
the distance covered will be : d = Vi*t + 1/2*a*t^2
where d is distance, Vi is initial speed, and a is acceleration
Then after 1 km which is 1000 metres we have:
1000 = Vi *71.2 + 1/2*0.0499*(71.2)^2
Vi = (1000-1/2*0.0499*(71.2)^2)/71.2 = 1000/71.2 - 1/2*0.0499*71.2 = 12.27 m/s
Then the car was going at 12.27 m/s when started to accelerate.</span>
