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evablogger [386]
3 years ago
5

One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

ways on the midpoint of the rope, displacing it a distance of 2 m (assume the car slides forward slightly in response to this, but then become stuck again). If he exerts a force of 87 N under these conditions, determine the force exerted on the car. Round your answer to one decimal place.

Physics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34  Solving for H:

H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

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Answer:

Explanation:

d = ½at²

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d = 24.5 m

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2 years ago
Which of the following is NOT common of elite Shang burials?
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Answer:

Large above ground mausoleums were not common in the elite Shang burials.

Explanation:

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An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of
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Answer;

=32.15 meters

Explanation;

Use the formula  

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where s= distance traveled  

u=initial velocity which is zero in this case  

t= time taken to travel 's' distance  

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )  

Therefore;

S = 0.5 * 1.62 * 6.3 * 6.3

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3 0
3 years ago
A student drops a 1.5 kg rock off of a 4.0 m tall bridge. The speed of the rock just before it hits the water below is 6 m/s. Ho
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Answer:

Energy due to air resistance = 31.8 Joules

Explanation:

According to the law of conservation of energy, energy can neither be created nor destroyed but can be transformed from one form to another

Kinetic Energy + Energy due to air resistance = Potential energy..........(1)

If there is no energy loss due to air resistance, potential energy = kinetic energy

mass, m = 1.5 kg

height, h = 4.0 m

speed, v = 6 m/s

Kinetic energy = 0.5 mv²

Kinetic energy = 0.5 * 1.5 * 6²

Kinetic energy = 27 Joules

Potential Energy = mgh

Potential energy = 1.5 * 9.8 * 4

Potential energy = 58.8 Joules

From equation (1)

27 + Energy due to air resistance = 58.8

Energy due to air resistance = 58.8 - 27

Energy due to air resistance = 31.8 Joules

8 0
2 years ago
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<span>the difference of electrical potential between two points. hope this helps</span>
3 0
3 years ago
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