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madreJ [45]
3 years ago
12

Le Châtelier’s principle states that increasing temperature favors a reaction that a. releases energy as heat. c. involves a che

mical catalyst. b. requires energy as heat. d. involves an enzyme.
Chemistry
2 answers:
xeze [42]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

According to Le Chatelier's principle, when a system is in a chemical equilibrium and it is facing a disturbance then the equilibrium will shift in the opposite direction which is opposing the disturbance.

Hence, when we increase the temperature of a chemical reaction then equilibrium will shift in the direction where energy in the form of heat is used.

Thus, we can conclude that Le Châtelier’s principle states that increasing temperature favors a reaction that  requires energy as heat.

Assoli18 [71]3 years ago
3 0
I think the correct answer would be <span>requires energy as heat. From the Le Chatelier's principle, when a reaction needs energy to react, increasing the temperature would favor the reaction. This is called an endothermic reaction. Hope this answers the question.</span>
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Which half-reaction correctly represents oxidation?
Leokris [45]

Answer: Mg\rightarrow Mg^{2+}+2e^- represents oxidation.

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Example: Mg\rightarrow Mg^{2+}+2e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Example: Mg^{2+}+2e^-\rightarrow Mg

Mg\rightarrow Mg^{2+}+2e^- represents oxidation.

4 0
3 years ago
Which statement best describes the formula equation cl1(g) + 2kbr(aq) —&gt; 2kcl(aq)+br2(i)
Zigmanuir [339]

Answer:

The chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Explanation:

Chemical equation:

Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)

Balanced chemical equation:

Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)

This equation showed that the chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.

The given equation is balanced and completely hold the law of conservation of mass.

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

8 0
3 years ago
he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
Two liquids, a and b are immiscible. liquid a has a density of 0.89 g/ml. liquid b has a density of 0.72 g/ml. what would you ex
Burka [1]
In the given above, we have two densities which are 0.89 g/mL and 0.72 g/mL. We are also given that the liquids are immiscible. After the settlement of the liquids, they will form two layers.

The heavier substance, the one which has a higher density will be at the bottom and the lighter substance, the one which has a lower density will be at the top layer.
5 0
3 years ago
when riding bumper cars at the fair you bump into your friend and your car bounces backwards which law of motion is this
weeeeeb [17]

Newton's third law of interaction, says that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body. It's the law of action-reaction, and it helps to explain why you feel a jolt when you collide with another bumper car.

6 0
3 years ago
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