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jarptica [38.1K]
3 years ago
10

Logic Puzzle: Determine the concentration in the eye dropper. Write the steps below. What is the concentration of the solution i

n the Eyedropper?

Chemistry
1 answer:
romanna [79]3 years ago
4 0

Answer: copper (II) Sulphate

Explanation:

a.) The concentration in the eye dropper is copper (II) tetraoxo sulphate (vi)

Which is also called copper (II) sulphate

b.) Copper sulfate is a chemical compound with the formula CuSO4 and can be made in a chemistry laboratory by reacting copper oxide with sulphuric acid.

Apparatus used are :

Safety goggles, Bunsen burner, tripod. Test tube, beaker, conical flask, funnel and filter paper.

Procedures:

Check that the air hole on the Bunsen burner is fully closed, and turn on the gas tap. Light a splint and hold it two inches over the top of the Bunsen burner to ignite the gas.

Pour 20 cm3 of the dilute sulphuric acid into the beaker. Open the air hole on the Bunsen burner to give a blue flame, and place the beaker on the tripod. Heat the sulphuric acid until almost boiling.

Add a small amount of the copper oxide powder into the beaker using a spatula. Stir the mixture for 30 seconds with the glass stirring rod. Repeat until one gram of copper oxide powder has been added.

Continue to heat for another two minutes to ensure the reaction has completed. Turn off the Bunsen burner and allow the beaker to cool slightly.

Place a funnel in the conical flask, and fold a filter paper to fit the funnel. Swirl the beaker gently to ensure the contents of the solution are mixed, then pour the solution slowly through the filter paper. This step removes any unreacted copper oxide remaining. Clear blue copper sulfate solution will be left in the flask. If there are any impurities remaining in the solution, repeat the filter process.

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Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)
kompoz [17]

Answer:

im not doing your whole homework. but ill give you  one cent ;>, whats ur paypal

Explanation:

4 0
3 years ago
What is the mass in grams of 4.50x10^16 atoms of K
vredina [299]

Answer:

The answer to your question is 2.92 x 10⁻⁶ g

Explanation:

Data

mass of K = ?

atoms of K = 4.50 x 10¹⁶

Process

To answer this question just remember that the atomic mass of any element is equivalent to Avogadro's number.

1.- Look for the atomic number of Potassium

Atomic number = 39.10 g

2.- Use proportions and cross multiplication

                 39.10 g of K --------------- 6.023 x 10²³ atoms

                      x              ----------------4.50 x 10¹⁶ atoms

                            x = (4.50 x 10¹⁶ x 39.10) / 6.023 x 10²³

-Simplify

                            x = 1.7595 x 10¹⁸ / 6.023 x 10²³

-Result

                            x = 2.92 x 10⁻⁶ g

7 0
4 years ago
7) The density of Cl2 gas at STP, in grams per liter, is approximately:
maria [59]

Answer:

Make me Brilliant

Explanation:

3.2 gl

4 0
3 years ago
A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?
Sonja [21]

Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.892 atm

P_2 = final pressure of gas = 1.05 atm

V_1 = initial volume of gas = 6.35 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 55.0^oC=273+55.0=328K

T_2 = final temperature of gas = 59.0^oC=273+59.0=332K

Now put all the given values in the above equation, we get:

\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}

V_2=5.46L

Thus, the final volume of gas will be, 5.46 L

7 0
3 years ago
A temperature of –25°C is equivalent to: Question 2 options: 25 K. 248 K. –25 K. 298 K.\
babunello [35]
First, to convert from C to K, add (C+273)=k
So -25+273=248
6 0
3 years ago
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