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Gala2k [10]
3 years ago
13

What is the mass in grams of 4.50x10^16 atoms of K

Chemistry
1 answer:
vredina [299]3 years ago
7 0

Answer:

The answer to your question is 2.92 x 10⁻⁶ g

Explanation:

Data

mass of K = ?

atoms of K = 4.50 x 10¹⁶

Process

To answer this question just remember that the atomic mass of any element is equivalent to Avogadro's number.

1.- Look for the atomic number of Potassium

Atomic number = 39.10 g

2.- Use proportions and cross multiplication

                 39.10 g of K --------------- 6.023 x 10²³ atoms

                      x              ----------------4.50 x 10¹⁶ atoms

                            x = (4.50 x 10¹⁶ x 39.10) / 6.023 x 10²³

-Simplify

                            x = 1.7595 x 10¹⁸ / 6.023 x 10²³

-Result

                            x = 2.92 x 10⁻⁶ g

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DochEvi [55]

Answer:

C.  physical

Explanation:

A mixture is a physical combination. Mixtures are combinations of compounds and molecules without any chemical reaction taking place.

Mixtures have the following properties:

  • They have an indefinite composition i.e they consist of two or more elements and or compounds in any proportion by mass
  • Their constituents retains their identities i. e physical property is retained.
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8 0
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What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
How many Ne atoms are contained in 32.0 g of the element?
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Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

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Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
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