Answer:
20 m/s
Explanation:
The frictional force the road exerts on the car provides the centripetal force that keeps the car in circular motion along the curve:
where
F is the centripetal force
m is the mass of the car
r is the radius of the curve
v is the speed of the car
In this problem we have:
m = 2000 kg
r = 200 m
F = 4000 N is the maximum force
Re-arranging the equation, we can calculate the maximum speed v corresponding to this force:
Answer:
5 m/s 2
To
get the acceleration of a car, you need to know first the difference in the
change in speed of a car then divided by time of the change. This can be
expressed as acceleration =
(change in speed) divided by (time for the change). So 30 m/s minus 10 m/s is
equal to 20 m/s divided by 4 seconds and the quotient is 5 m/s2.
Answer:
a = -47.93 m/s²
Explanation:
given,
speed of particle in positive x-direction, u = 97 m/s
speed of particle in opposite direction, v = -42 m/s
time = 2.9 s
average acceleration, a = ?
now,
a = -47.93 m/s²
Hence, the average acceleration is equal to -47.93 m/s²
Answer:A
Explanation:
Explanation:
Given that,
Gravitational force = 600 N
Frictional force = 25 N
Pulled by the Force = 250 N
We know that,
The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.
The balance equation is along y-axis
The box will not move in y-axis therefore, the net force in the y-axis will be zero.
Hence, The net force in the y-direction will be zero.
Answer:
c
Explanation:
the loud noise can reduce the quality of the analog signal