B = (1/6).π.x².s
1st Multiply both sides with 6 → 6B = (6).(1/6).π.x².s. Simplify by 6
6B = π.x².s. Now divide both sides by .π.x².
6B/(.π.x²) = .(π.x².s)/(.π.x²) After simplification you get:
6B/(.π.x²) = s → s = 6B/(.π.x²)
They are congruent by SSS
triangle ANP is congruent to triangle LCK is one of several possibilities for question B
Answer:
Step-by-step explanation:
-2x - 7
