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Lana71 [14]
3 years ago
13

Neutral atoms of neon (atomic number 10) have the same number of electrons as each of the following except:

Chemistry
2 answers:
4vir4ik [10]3 years ago
8 0

Answer : The correct option is, Ar

Explanation :

(1) The element is, Na^+

Atomic number of Na = 11

The general electronic configuration of Na is, 1s^22s^22p^63s^1

The electronic configuration of Na^+ is, 1s^22s^22p^6

The number of electrons in Na^+ = 10

(2) The element is, Mg^{2+}

Atomic number of Mg = 12

The general electronic configuration of Mg is, 1s^22s^22p^63s^2

The electronic configuration of Mg^{2+} is, 1s^22s^22p^6

The number of electrons in Mg^{2+} = 10

(3) The element is, F^-

Atomic number of F = 9

The general electronic configuration of F is, 1s^22s^22p^5

The electronic configuration of F^- is, 1s^22s^22p^6

The number of electrons in F^- = 10

(4) The element is, Ar

Atomic number of Ar = 18

The general electronic configuration of Ar is, 1s^22s^22p^63s^23p^6

The number of electrons in Ar = 18

(5) The element is, O^{2-}

Atomic number of O = 8

The general electronic configuration of O is, 1s^22s^22p^4

The electronic configuration of O^{2-} is, 1s^22s^22p^6

The number of electrons in O^{2-} = 10

From this we conclude that, the option 1, 2, 3 and 5 have the same number of electrons as the neutral atom of neon. While in 'Ar' there are 18 number of electrons.

Hence, the correct option is, Ar

HACTEHA [7]3 years ago
6 0
The answer would be : Ar.

Hope this helps !

Photon
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Answer:

0.10L of 1.00M of H₃PO₄ and 0.1613L of 1.00M NaOH

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The pKa's of phosphoric acid are:

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To have a 50mM solution of phosphoures we need:

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Using H-H equation we can find the amount of NaOH added:

pH = pKa + log [A⁻] / [HA] <em>(1)</em>

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Replacing (2) in (1):

7.40 = 7.20 + log 0.10mol - [HA] / [HA]

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That means moles of HPO₄²⁻ are 0.10mol - 0.0387moles = 0.0613 moles

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Total moles of NaOH are 0.1613moles * (1L / 1mol) = 0.1613L of 1.00M NaOH

Then, you need to dilute both solutions to 2.00L with distilled water.

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