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yulyashka [42]
3 years ago
15

How do you do these?

Chemistry
1 answer:
Agata [3.3K]3 years ago
6 0

Solve these problems like weighted averages:

The first one:

Multiply the masses (isotope numbers) by the decimal form of the percentage. Add them

0.076 (6) + 0.924 (7) = 6.924


The second one:

0.2 (10) + 0.8 (11) = 10.8


If you think about it, these answers make sense. 6.924 is much closer to 7 than to 6 (since there's a lot more lithium-7 than there is lithium-6). 10.8 is closer to 11 than to 10.


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A spring toy is moving down steps, What happens to the energy of the toy?
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When the toy is falling down the steps some of the Kinetic energy is changing to potential energy. As it is still falling some of the potential energy changes to kinetic energy.


Hope this helps
7 0
3 years ago
Explain what happens to the light ray when it travels through air and then into water
NemiM [27]

A Change of Course. Light travels faster through air than it does through a denser substance, such as water or glass.

So, when light rays travel through air and meet the surface of the denser substance, they are suddenly slowed down.

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6 0
3 years ago
Read 2 more answers
Convert 632 mmHg to kPa
Ilia_Sergeevich [38]
Answer:
84.259 kPa

Explanation:
We know that:
1 kPa is approximately equal to 7.5 mmHg
Therefore, to convert 632 mmHg to kPa, we will simply use cross multiplication as follows:
1 kPa .................> 7.5006 mmHg
?? kPa ................> 632 mmHg
632 mmHg = (632*1) / (7.5006) = 84.259 kPa

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3 0
3 years ago
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A 3L sample of an ideal gas at 178 K has a pressure of 0.3 atm. Assuming that the volume is constant, what is the approximate pr
harina [27]

Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

Explanation:

Given: T_{1} = 178 K,      P_{1} = 0.3 atm

T_{2} = 278 K,           P_{2} = ?

According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.

Formula used to calculate the pressure is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\

Substitute the values into above formula is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{0.3 atm}{178 K} = \frac{P_{2}}{278 K}\\P_{2} = 0.468 atm

Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

3 0
3 years ago
Observation And Assessment
Sloan [31]
I'm confused here??????
5 0
3 years ago
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